convert into c++ program
In this python program convert into c++ program. Thank you
Source Code:
print("The function is f(x)= 2x+3(2)")
print("Width is 0.05")
lowLim=float(input("Enter Lower Limit: "))
upperLim=float(input("Enter Upper Limit: "))
iterations = (upperLim - lowLim)/0.05
i=0
finAns = 0
while(i<iterations):
print("_________________________________________________________________________________________________________________________________")
print("Iteration:",(i + 1))
print("Function\t\t|\tLower Limit \t|\t Upper Limit \t|\t LRAM Application (width=0.05) \t|\t Answer")
initAns=((2*lowLim)+(3*2))*0.05
print("f(x)= 2x+3(2) \t\t|\tx={:0.2f}\t\t|\tx={:0.2f}\t\t|\t f(x) = (2({:0.2f})+3(2) * 0.05\t|\t {:0.2f}".format(lowLim,lowLim+0.05,lowLim,initAns))
finAns += initAns
lowLim+=0.05
i += 1
print("_________________________________________________________________________________________________________________________________")
print("Final answer/Summation of all iterations is:",finAns)
..
See the picture below that's a output sample output of this program
![Upper Limit
x=1.35
|Answer
Function
T
T
LRAM Application (width=0.05)
f(x) = (2(1.30)+3(2) * 0.05
Lower Limit
f(x)= 2x+3(2)
X=1.30
0.43
Iteration: 8
! Upper Limit
x=1.40
Function
Lower Limit
| x=1.35
LRAM Application (width=0.05) |
f(x) = (2(1.35)+3(2) * 0.05
Answer
f(x)= 2x+3(2)
0.44
Iteration: 9
! Upper Limit
x=1.45
|
LRAM Application (width=0.05) |
Function
Lower Limit
Answer
0.44
f(x)= 2x+3(2)
x=1.40
f(x) = (2(1.40)+3(2)
ө.05
Iteration: 10
Upper Limit
x-1.50
LRAM Application (width=0.e5) I
f(x) = (2(1.45)+3(2) * 0.05
Function
Lower Limit
Answer
f(x)- 2х+3(2)
X=1.45
0.45
Iteration: 11
I Lower Limit
x=1.50
|
Upper Limit
x=1.55
LRAM Application (width=0.05) |
f(x) = (2(1.50)+3(2) * 0.05
Function
Answer
f(x)= 2x+3(2)
0.45
Iteration: 12
I LRAM Application (width=e.05) |
f(x) = (2(1.55)+3(2)
Function
Lower Limit
! Upper Limit
Answer
0.46
f(x)= 2x+3(2)
x=1.55
x=1.60
0.05
Iteration: 13
Lower Limit
| x=1.60
Upper Limit
x=1.65
LRAM Application (width=0.e5) |
f(x) = (2(1.60)+3(2) * 0.05
Function
Answer
f(x)= 2x+3(2)
ө.46
Iteration: 14
Upper Limit
x=1.70
| LRAM Application (width=0.e5) |
f(x) = (2(1.65)+3(2) * 0.05
Function
Lower Limit
Answer
f(x)= 2x+3(2)
x=1.65
0.47
Iteration: 15
Function
LRAM Application (width=0.05) I
f(x) = (2(1.70)+3(2) * 0.05
Lower Limit
Upper Limit
Answer
f(x)= 2x+3(2)
x=1.70
x=1.75
0.47
Iteration: 16
Function
f(x)= 2x+3(2)
Lower Limit
Upper Limit
x=1.80
LRAM Application (width=0.e5) I
F(x) = (2(1.75)+3(2) * 0.05
Answer
x=1.75
0.48
Iteration: 17
Function
Upper Limit
x-1.85
| LRAM Application (width=0.e5) |
f(x) = (2(1.8e)+3(2) • 0.05
Lower Limit
Answer
f(x)= 2x+3(2)
X=1.80
0.48
Iteration: 18
Function
Lower Limit
Upper Limit
LRAM Application (width=0.05) |
Answer
0.49
f(x)= 2x+3(2)
x=1.85
x=1.90
F(x) = (2(1.85)+3(2) * 0.05
Iteration: 19
Function
f(x)= 2x+3(2)
! Upper Limit
X=1.95
LRAM Application (width=0.05) |
f(x) = (2(1.90)+3(2)
Lower Limit
Answer
x=1.90
0.49
Iteration: 20
LRAM Application (width=0.05) |
f(x) = (2(1.95)+3(2) * 0.05
Function
Lower Limit
Upper Limit
Answer
f(x)= 2x+3(2)
| x=1.95
x=2.00
0.50
Final answer/Summation of all iterations is: 8.95
--](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0091710a-db5e-4a71-a04b-b7b07210131d%2F74b807a8-9560-42d3-bed5-4670ea62b439%2F4ne675xmxk_processed.png&w=3840&q=75)
![The function is f(x)= 2x+3(2)
Width is 0.05
Enter Lower Limit: 1
Enter Upper Limit: 2
Iteration: 1
Function
f(x)= 2x+3(2)
! Upper Limit
x=1.05
Lower Limit
LRAM Application (width=0.05)
f(x) = (2(1.00)+3(2)
Answer
0.40
x=1.00
* 0.05
Iteration: 2
Lower Limit
x=1.05
|
LRAM Application (width=0.e5) |
f(x) = (2(1.e5)+3(2) • 0.05
Function
Upper Limit
Answer
f(x)= 2x+3(2)
X=1.10
0.41
Iteration: 3
LRAM Application (width=0.05)
f(x) = (2(1.10)+3(2) * 0.05
Function
Lower Limit
Upper Limit
Answer
f(x)= 2x+3(2)
X=1.10
x=1.15
0.41
Iteration: 4
Lower Limit
I x=1.15
LRAM Application (width=0.05) |
f(x) = (2(1.15)+3(2) * 0.05
Function
Upper Limit
Answer
f(x)= 2x+3(2)
x=1.20
0.42
Iteration: 5
Upper Limit
LRAM Application (width=0.05) |
f(x) = (2(1.20)+3(2) * 0.05
Function
Lower Limit
Answer
f(x)= 2x+3(2)
x=1.20
x=1.25
0.42
Iteration: 6
Function
f(x)= 2x+3(2)
LRAM Application (width=0.05) I
f(x) = (2(1.25)+3(2) * 0.05
Lower Limit
Upper Limit
x=1.30
Answer
X=1.25
0.43
Iteration: 7
Function
f(x)= 2x+3(2)
Lower Limit
x=1.30
Upper Limit
x=1.35
LRAM Application (width=0.05) |
F(x) = (2(1.30)+3(2) * 0.05
Answer
0.43
Iteration: 8
Function
f(x)= 2x+3(2)
Upper Limit
I LRAM Application (width=e.05) |
f(x) = (2(1.35)+3(2) * 0.05
Lower Limit
!
x=1.40
Answer
x=1.35
0.44
Iteration: 9
Function
f(x)= 2x+3(2)
Upper Limit
x=1.45
LRAM Application (width=0.05) |
f(x) = (2(1.40)+3(2) * 0.05
Lower Limit
Answer
x=1.40
0.44
Iteration: 10
Function
f(x)= 2x+3(2)
Upper Limit
x-1.50
LRAM Application (width=0.05) |
f(x) = (2(1.45)+3(2) * 0.05
Lower Limit
Answer
x=1.45
0.45
Iteration: 11
Lower Limit
| x=1.50
! Upper Limit
x=1.55
Function
|
LRAM Application (width=0.05) |
Answer
f(x)= 2x+3(2)
f(x) = (2(1.50)+3(2) * 0.05 I
0.45
Iteration: 12
Function
f(x)= 2x+3(2)
LRAM Application (width=0.05) |
f(x) = (2(1.55)+3(2) * 0.05
Lower Limit
Upper Limit
Answer
x=1.55
X=1.60
ө.46
Iteration: 13
Function
f(x)= 2x+3(2)
LRAM Application (width=0.05) |
f(x) = (2(1.60)+3(2) * 0.05
Lower Limit
! Upper Limit
Answer
x=1.60
x=1.65
0.46
----. 14](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0091710a-db5e-4a71-a04b-b7b07210131d%2F74b807a8-9560-42d3-bed5-4670ea62b439%2Fm45wvo_processed.png&w=3840&q=75)
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