Conversely, suppose y belongs to Col Q. Then y = Qx for some x. Since R is invertible, what does the equation A = QR imply? O A. Q= AR 1 O B. A=Q. OC. Ais invertible. O D. Q=R¯'A So y = which shows that y is in Col A. AQx = A(Qx) R-Ax = (R-A)x AR 'x= A(R 'x) Click to AR ´x= (AR¯1)x
Conversely, suppose y belongs to Col Q. Then y = Qx for some x. Since R is invertible, what does the equation A = QR imply? O A. Q= AR 1 O B. A=Q. OC. Ais invertible. O D. Q=R¯'A So y = which shows that y is in Col A. AQx = A(Qx) R-Ax = (R-A)x AR 'x= A(R 'x) Click to AR ´x= (AR¯1)x
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Conversely, suppose y belongs to Col Q. Then y = Qx for some x. Since R is invertible, what does the equation A = QR imply?
A. Q= AR 1
O B. A=Q.
OC. Ais invertible.
O D. Q=R 'A
So y =
, which shows that y is in Col A.
AQx = A(Qx)
R-Ax = (R-'A)x
AR x=A (R 'x)
AR x = (AR 1)x
Click to
%3D
![Suppose A = QR where R is an invertible matrix, Show that
and Q have the same column space. [Hint: Given y in Col A, show that y = Qx for some x. Also, given y in Col Q, show that y = Ax for some x.]
If y is in Col A, then which of these is true?
O A. y= QR.
O B. y is in Col R.
O C. x= Ay for some x.
O D. y= Ax for some x.
Then y =
which shows that y is a linear combination of the columns of Q using the entries in Rx as weights. Therefore, y belongs to Col Q.
Converse
Col Q. Then y = Qx for some x. Since R is invertible, what does the equation A = QR imply?
O A. Q
QRx = (QR)x
O B. A
QRx = Q(Rx)
O c. A
O D. Q
xQR = (xQ)R
So y =
xQR = x(QR)
ch shows that y is in Col A.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc5941ae9-6ead-4355-86dd-455bc2b61a77%2Fd21a4bed-8900-43e3-8d86-ec0a1b0b0104%2Fdt0qphf_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose A = QR where R is an invertible matrix, Show that
and Q have the same column space. [Hint: Given y in Col A, show that y = Qx for some x. Also, given y in Col Q, show that y = Ax for some x.]
If y is in Col A, then which of these is true?
O A. y= QR.
O B. y is in Col R.
O C. x= Ay for some x.
O D. y= Ax for some x.
Then y =
which shows that y is a linear combination of the columns of Q using the entries in Rx as weights. Therefore, y belongs to Col Q.
Converse
Col Q. Then y = Qx for some x. Since R is invertible, what does the equation A = QR imply?
O A. Q
QRx = (QR)x
O B. A
QRx = Q(Rx)
O c. A
O D. Q
xQR = (xQ)R
So y =
xQR = x(QR)
ch shows that y is in Col A.
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