1d³y dx3 a.) x² + secxy c.) (y³ − y + 1)dx + - 4x √x+1 b.) x(y' - xy) = (x² + x−²)y5 e.) y' - x = 2yy' = 0 x² x³-1 dy = 0 d.) y sec²(xy) dx + x sec²(xy) = 0

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