Control 27.64 29.63 29.36 25.67 31.43 32.41 33.66 28.84 30.03 29.37 31.82 27.18 32.55 Castration 24.65 27.68 28.53 29.61 26.72 28.19 28.64 27.47 28.21 29.52 If we wished to know whether we could do a homoscedastic t test (or have no choice and must do a heteroscedastic test) we need to do a preliminary F ratio test. Conduct a F ratio test. (Use the F tables online for the critical value). Report non-integer values to closest 0.001. Calculate the following values: Q1-4. df(num) = ??? df(den) = ??? Fcalc = ??? Ferit (a=0.05) = ??? Perform a two-tailed t test of the data. If the results above allow a homoscedastic test to be used, do that, otherwise perform a heteroscedastic t test. Report values to closest 0.001, but round df to the appropriate whole number if you use a heteroscedastic t test. Calculate the following values: Q5-7. df = ??? tcalc = ??? torit (a=0.05)=??? Q8. Choose the statement that best matches the conclusion of your t test. Your choices will be: The male baboons in the castration treatment have a significantly smaller mean mass than the control males (p < 0.01). The male baboons in the castration treatment have a significantly smaller mean mass than the control males (0.01 < p < 0.02). The male baboons in the castration treatment have a significantly smaller mean mass than the control males (0.02 < p < 0.04). The male baboons in the castration treatment have a significantly smaller mean mass than the control males (0.04 < p < 0.05). The male baboons in the castration treatment have a significantly smaller mean mass than the control males (0.05 < p). There is no significant difference between the mean body masses of male baboons in the two treatment (p < 0.01). There is no significant difference between the mean body masses of male baboons in the two treatment (0.01 < p < 0.02). There is no significant difference between the mean body masses of male baboons in the two treatment (0.02 < p < 0.04). There is no significant difference between the mean body masses of male baboons in the two treatment (0.04 < p < 0.05). There is no significant difference between the mean body masses of male baboons in the two treatment (0.05 < p).