### Potential Difference Across the 6 Ω ResistorContinuing with the same setup as above, where you connect a 6 Ω resistor and a 12 Ω resistor in series to a 9 V battery. Find the potential difference, V1, across the 6 Ω resistor in Volts.**Hint:** VTot = V1 = V2.### Circuit Diagram ExplanationThe circuit diagram illustrates two resistors, R1 and R2, connected in series with a 9V battery (BAT1).- **R1 = 6 Ω**: The first resistor has a resistance of 6 Ohms.- **R2 = 12 Ω**: The second resistor has a resistance of 12 Ohms.- **BAT1 = 9 V**: The battery provides a potential difference of 9 Volts.The total resistance \( RTot \) is the sum of R1 and R2 because they are in series:\[ RTot = R1 + R2 \]\[ RTot = 6 \, \Omega + 12 \, \Omega \]\[ RTot = 18 \, \Omega \]The total current \( ITot \) through the series circuit can be found using Ohm's Law:\[ ITot = \frac{V_{Tot}}{R_{Tot}} \]\[ ITot = \frac{9 \, V}{18 \, \Omega} \]\[ ITot = 0.5 \, A \]The potential difference \( V1 \) across the 6 Ω resistor can be found by multiplying the current \( ITot \) by the resistance \( R1 \):\[ V1 = ITot \times R1 \]\[ V1 = 0.5 \, A \times 6 \, \Omega \]\[ V1 = 3 \, V \]Therefore, the potential difference across the 6 Ω resistor is \( 3 \, V \). ### Basic Electrical Equations and Concepts#### Ohm's Law:- \( V = IR \)- \( I = \frac{V}{R} \)- \( R = \frac{V}{I} \)### Series Circuits:- Total Current: \( I_{\text{Tot}} = I_1 = I_2 \)- Total Voltage: \( V_{\text{Tot}} = V_1 + V_2 \)- Total Resistance: \( R_{\text{Tot}} = R_1 + R_2 \)### Parallel Circuits:- Total Current: \( I_{\text{Tot}} = I_1 + I_2 \)- Total Voltage: \( V_{\text{Tot}} = V_1 = V_2 \)- Total Resistance:\[ \frac{1}{R_{\text{Tot}}} = \frac{1}{R_1} + \frac{1}{R_2} \]or\[ R_{\text{Tot}} = \frac{R_1 \cdot R_2}{R_1 + R_2} \]These equations provide the fundamental relationships between voltage (V), current (I), and resistance (R) in electrical circuits, both in series and parallel configurations. Understanding these relationships is crucial for analyzing and designing electrical circuits.

R1=6Ω; R2=12Ω; V=9V to find potential difference V1 across 6Ω resistor in volts

Continuing with the same setup as above, where you connect a 6Q resistor and a 12 Q resistor in series to a 9 V battery. Find the potential difference, V1, across the 62 resistor in Volts. Hint: VTot = V1 = V2. RTot ITot +. R1 R2 BAT1 12Ω 9 V

Continuing with the same setup as above, where you connect a 6Q resistor and a 12 Q resistor in series to a 9 V battery. Find the potential difference, V1, across the 62 resistor in Volts. Hint: VTot = V1 = V2. RTot ITot +. R1 R2 BAT1 12Ω 9 V

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

WHEN COMBINING RESISTORS IN SERIES, THE TOTAL COMBINED RESISTANCE WILL BE EQUAL TO O A. THE SUM OF ALL THE RECIPROCALS OF EACH INDIVIDUAL RESISTANCE IN SERIES. O B. THE SUM OF ALL THE RESISTANCES IN SERIES. O C. THE PRODUCT OF ALL THE RESISTANCES IN SERIES. O D. THE RECIPROCAL OF THE SUM OF RECIPROCALS OF EACH INDIVIDUAL RESISTANCE IN SERIES.
If the effective voltage across a resistor is 2.2 v, then The maximum voltage is: Select one: O a. 4 V O b. 2 V C. 8 V O d. None of these
An inductor and resistor are connected in parallel to a 120-V, 60-Hz line. The resistor has a resistance of 50 ohms, and the inductor has an inductance of 0.2 H. What is the total current flow through the circuit?
The voltage divider shown in the figure has a potential difference (V) between point A and B and a potential difference (VO) between points C and D. What is V FO? A B RM 2R O A. 2 OB. 4 O C.3 OD. S M 2R R :2R C D
Three identical 2-0 resistors when combined in any manner possible whether in simple or compound circuit cannot have an effective resistance of* 0.75 0 3.0 0 0.67 0 O 6.0 0 A 20-V potential difference is applied across a series combination of a 10- N and a 30-0 resistor. The POTENTIAL DROP in the 30-0 resistor is 5.0 V O 10.0 V 20.0 V 15.0 V
Find volatge and current across each resistor .first perform delta to wye conversion then use current and voltage divider rule to find current and voltage across each resistor
How much energy must a 24-V battery expend to chargea 0.45 µ F and a 0.20µ F capacitor fully when they areplaced (a) in parallel, (b) in series? (c) How much chargeflowed from the battery in each case?
Determine I, V1, V2, and V, for the series de configuration + V, R, E, = 10 VoMm 4.7 ka Si R222 k2 v: E, =-5 V
Question 4 on for > 0 as shown in Figure 1 below. What is the power? A 20te The independent current source in the circuit generates zero current for < 0 and a pulse of O a g0re-10: b. 301 e101 W -101 900e -10t o. 130te W. O d.1201 e -10z -10t 600te W
Determine the voltage across R2 in the figure below, if the source is 6V, the Zener is 5.2V, R1= 10k ohms, and R2= 10k ohms.
C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot…
Needed to be solved correclty in 30 minutes and get the thumbs up please show neat and clean work. Please by hand solution is needed