Content Tuno bore to coarch 40 Ω 50 2 o MI M Inbox (465)-jsk244@nau.edu n ProblemID=181498761 ▼ • For a battery with current in the positive-to-negative direction: AVbat = -(Figure 2) For a resistor: AVR-IR(Eigure 3) 4. Apply the loop law: Part A Part B Find the current I in the circuit shown in the figure. (Eigure 5) Express your answer in amperes. View Available Hint(s) I= IVE ΑΣΦ Submit Part C X + Provide Feedback w ? A D o ΣΔ΄ - 0 a d h for F a 12 M V * O < a O 4 of 9 Review | Constants. Next > > 11:17 PM X I B

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<HW 25-1
Item 4
↓
Mastering Physics: HW 25-1
session.masteringphysics.com/myct/itemView?assignmentProblemID=181498761
Learning Goal:
To practice Tactics Box 25.1 Using Kirchhoff's loop law.
Circuit analysis is based on Kirchhoff's laws, which can be
summarized as follows:
• Kirchhoff's junction law says that the total current into
a junction must equal the total current leaving the
junction.
• Kirchhoff's loop law says that if we add all of the
potential differences around the loop formed by a
circuit, the sum of these potential differences must be
zero
While Kirchhoff's junction law is needed only when there are one or
Figure
9.0 V-
X
+
Type here to search
40 Ω
ww
50 Ω
O
5 of 6
I
-
X M Inbox (465) -jsk244@nau.edu - X +
• For a battery with current in the positive-to-negative direction: AV bat
• For a resistor: AVR-IR. (Figure 3)
4. Apply the loop law:
Part A
Part B
Find the current I in the circuit shown in the figure. (Figure 5)
Express your answer in amperes.
► View Available Hint(s)
I =
IVE ΑΣΦ
Submit
Part C
Provide Feedback
J
✔
?
A
€
-E. (Figure 2)
Σ Δ΄; = 0
(DELI)
GE 59°F
<
☐
4 of 9
Review | Constants
Next >
11:17 PM
4/19/2023
>
x
⠀
Transcribed Image Text:Content <HW 25-1 Item 4 ↓ Mastering Physics: HW 25-1 session.masteringphysics.com/myct/itemView?assignmentProblemID=181498761 Learning Goal: To practice Tactics Box 25.1 Using Kirchhoff's loop law. Circuit analysis is based on Kirchhoff's laws, which can be summarized as follows: • Kirchhoff's junction law says that the total current into a junction must equal the total current leaving the junction. • Kirchhoff's loop law says that if we add all of the potential differences around the loop formed by a circuit, the sum of these potential differences must be zero While Kirchhoff's junction law is needed only when there are one or Figure 9.0 V- X + Type here to search 40 Ω ww 50 Ω O 5 of 6 I - X M Inbox (465) -jsk244@nau.edu - X + • For a battery with current in the positive-to-negative direction: AV bat • For a resistor: AVR-IR. (Figure 3) 4. Apply the loop law: Part A Part B Find the current I in the circuit shown in the figure. (Figure 5) Express your answer in amperes. ► View Available Hint(s) I = IVE ΑΣΦ Submit Part C Provide Feedback J ✔ ? A € -E. (Figure 2) Σ Δ΄; = 0 (DELI) GE 59°F < ☐ 4 of 9 Review | Constants Next > 11:17 PM 4/19/2023 > x ⠀
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