Construct the 99% confidence interval for the difference μ1 - μ2 when x1 = 476.88, = x2 = 318.32, s1 = 42.11, s2 = 26.80, n1 = 19, and n2 = 22. Use tables to find the critical value and round the answers to at least two decimal places.A 99% confidence interval for the difference in the population means is___ < μ1 - μ2 < ___.image attached bellow for better view. Construct the 99% confidence interval for the difference μ₁ −μ₂ when x₁=476.88, x₂=318.32, s₁=42.11, s₂=26.80, n₁=19, and n₂=22. Use tables tofind the critical value and round the answers to at least two decimal places.A 99% confidence interval for the difference in the population means is< μη – με <×S

Given that x¯1=476.88,x¯2=318.32,s1=42.11,s2=26.80,n1=19,n2=22.Since no information about the population standard deviations are equal. Assume the population standard deviations are equal. The pooled variance is, sp2=n1-1s12+n2-1s22n1+n2-2=19-142.112+22-126.80219+22-2=47001.577839=1205.1687 The degrees of freedom is, df=n1+n2-2=19+22-2=39 By using the EXCEL, the critical value is, The 99% confidence interval for the difference in the population means is, x¯1-x¯2-tcritsp21n1+1n2<μ1-μ2<x¯1-x¯2+tcritsp21n1+1n2476.88-318.32-2.70791205.1687119+122<μ1-μ2<476.88-318.32+2.70791205.1687119+122158.56-29.44<μ1-μ2<158.56+29.44129.12<μ1-μ2<188.00 Thus, the 99% confidence interval for the difference in the population means is 129.12<μ1-μ2<188.00.