construct the 95% and 99% confidence intervals for the population proportion p using the indicated sample statistics. Which interval is wider? If convenient, use technology to construct the confidence intervals. 1) Charity In a survey of 2939 U.S. adults, 2439 say they have contributed to a charity in the past 12 months.

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

A:

Q: Construct a 99.8% confidence interval for the proportion of women who work at home who are college…

A: Given,n=519x=165p^=xnp^=165519=0.318The point estimation for the proportion is 0.318 .

Q: n a survey of 2558 ​adults, 1413 say they have started paying bills online in the last year.…

A: Solution: Given information: n= 2558 Sample size of adults  x = 1413 adults started paying bills…

Q: In a survey of 2549 adults in a recent​ year, 1270 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: In a survey of 3478 adults, 1462 say they have started paying bills online in the last year.…

A: From the provided information,Confidence level = 99%

Q: In a survey of 2703 ​adults, 1438 say they have started paying bills online in the last year.…

A: We have given that, Number of favorable cases(X) = 1438,   Sample size(n) = 2703 Sample proportion…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Suppose we take a survey of 200 students and ask how much they study per week. The result is an…

A: From the above data  We are given that the  95% confidence interval is (10, 10.5). The population…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

A:

Q: In a survey of 2405 adults in a recent​ year, 1217 say they have made a New Year's resolution.…

A: Given: n=2405 x=1217

Q: In a survey of 2542 adults in a recent​ year, 1487 say they have made a New​ Year's resolution.…

A: Given,  n = 2542 x = 1487 proportion p  = 1487/2542                       = 0.5850

Q: In a survey of 50,00 people, 80% indicated that they listened to their favorite radio station…

A: Hern= 5000 P^ = 0.80 We have to construct 95% ci for p

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 500…

A:

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 2407 adults in a recent​ year,1468 say they have made a New​ Year's resolution.…

A: Given that,  Sample size, n= 2407 And X= 1468 We know that proportion, p=X/n So p= 1468/2407 p=…

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2000 adults in a recent​ year 1404, say they have made a New​ Year's resolution.…

A: n=2000x=1404

Q: The National Longitudinal Study of Adolescent Health interviewed several thousand teens (grades 7 to…

A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

Q: Construct a​ 99% confidence interval for the population proportion. Interpret the results.

A:

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: In a survey of 3102 adults,1401 say they have started paying bills online in the last year.…

A: Obtain the 99% confidence interval for the true population proportion. The 99% confidence interval…

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…

Q: 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare…

A: Answer Favorable cases [x] = 1230The sample size [n] = 2105

Q: n a survey of 2847 ​adults, 1408 say they have started paying bills online in the last year.…

A: Given that  Sample size (n) =2847 People started paying bills online (x) = 1408 Proportion (p) =…

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: In a survey of 3426 ​adults, 1487 say they have started paying bills online in the last year.…

A: From the provided information, Sample size (n) = 3426 Out of which 1487 say they have started paying…

Q: In a survey of 2417 adults in a recent​ year, 1458 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2497 adults in a recent​ year, 1383 say they have made a New​ Year's resolution.…

A: The sample size (n) is 2497 and the value of x is 1383.

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: In a survey of 2588 ​adults, 1466 say they have started paying bills online in the last year.…

A: Construct 99% confidence interval for population proportion:The sample of 2,588 adults among that…

Q: In a survey of 2554 adults in a recent​ year, 1357 say they have made a New​ Year's resolution.…

A:

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: A recent survey of 349 people ages 18 to 29 found that 86% of them own a smartphone. Find the 99%…

A: The 99% confidence interval of the population proportion is obtained below as follows:   The formula…

Q: In a survey of 74 US females, 56 said they had gone to the dentist within the past year. What is…

A: Given X=56 n=74

Q: Of 848 children surveyed, 144 plan to join a volunteer group in the future. Construct a 90%…

A: We have given that n=848, X=144, C.I=90%=0.90