Construct a curve for the titration of 20.00 mL 0.500 N succinic acid (HO2CCH2CH2CO2H) by 0.1000 N NaOH solution. Use MS Excel for convenience. Titrant volumes: 0.00 mL, 5.00 mL, 10.00 mL, 15.00 mL, 20.00 mL, 25.00 mL, and 30.00 mL. (CH2)2(CO2H)2⇄(CH2)2(CO2H)(CO2)^- +H^+ Ka1= 6.21 x 10^-5; pKa1 =4.207(CH2)2(CO2H)(CO2)^-⇄(CH2)2(CO2)2^2-+ H^+ Ka2= 2.31 x 10^-6; pKa2 =5.636 3. Construct a curve for the titration of 20.00 mL 0.0500 N succinic acid (HO;CCH;CH,CO,H)by 0.1000 N NaOH solution. Use MS Excel® for convenience. Titrant volumes: 0.00 mL,5.00 mL, 10.00 mL, 15.00 mL, 20.00 ml, 25.00 mL, and 30.00 mL.(CH)2(CO2H)2 = (CH2)2(CO2H)(CO2) + H*(CH.)2(CO,H)(CO.) (CH2)2(CO2), + H*Kai = 6.21 x 10s; pKai = 4.207Ka2 = 2.31 x 106; pK2 = 5.636%3!%3D%3!

We can build the bend for titration of corrosive against a base by taking the pH on the y-pivot and…

Answered: Construct a curve for the titration of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Question

Construct a curve for the titration of 20.00 mL 0.500 N succinic acid (HO2CCH2CH2CO2H) by 0.1000 N NaOH solution. Use MS Excel for convenience. Titrant volumes: 0.00 mL, 5.00 mL, 10.00 mL, 15.00 mL, 20.00 mL, 25.00 mL, and 30.00 mL.

(CH2)2(CO2H)2⇄(CH2)2(CO2H)(CO2)^- +H^+ Ka1= 6.21 x 10^-5; pKa1 =4.207

(CH2)2(CO2H)(CO2)^-⇄(CH2)2(CO2)2^2-+ H^+ Ka2= 2.31 x 10^-6; pKa2 =5.636

3. Construct a curve for the titration of 20.00 mL 0.0500 N succinic acid (HO;CCH;CH,CO,H)
by 0.1000 N NaOH solution. Use MS Excel® for convenience. Titrant volumes: 0.00 mL,
5.00 mL, 10.00 mL, 15.00 mL, 20.00 ml, 25.00 mL, and 30.00 mL.
(CH)2(CO2H)2 = (CH2)2(CO2H)(CO2) + H*
(CH.)2(CO,H)(CO.) (CH2)2(CO2), + H*
Kai = 6.21 x 10s; pKai = 4.207
Ka2 = 2.31 x 106; pK2 = 5.636
%3!
%3D
%3!

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions