Quiz#5onlinestatistics - WordaAaBbC AaBbCct AaB AaBbcct AaBbCcD AaBbCcD AaBbCcD AaBbCcD AaBbCcD AaBbCcD AABBCCDHeading 1 Heading 2TitleSubtitleSubtle Em...Emphasis Intense E... Strong Quote Intense Q... Subtle Ref....Stylesa.Tyron GrantConstruct a 95% confidence interval for the mean amount of protein in the new protein bar"Energize Original" if the amount of protein in the bars is normally distributed, you sampled18 of the bars and found the mean amount of protein was x = 18.2 grams with samplestandard deviation, (s) equaling 0.87 grams of protein.Come up with a one or two sentence summary regarding the confidence intervalthat you found in part c.S18 0.FindReplaceSelectEditingDicVa

We have given Sample size =18Sample mean =18.2Sample standard deviation =0.87Formula Used for…

Answered: Construct a 95% confidence interval for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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a. What is the R-squared (R2) value? Interpret this value in context of the study. b. What is the estimated variance of the response, σ^2 ?
You are interested in estimating the the mean weight of the local adult population of female white-tailed deer (doe). From past data, you estimate that the standard deviation of all adult female white-tailed deer in this region to be 22 pounds. What sample size would you need to in order to estimate the mean weight of all female white-tailed deer, with a 94% confidence level, to within 6 pounds of the actual weight?
A single question with sub-parts. Please answer all parts. I appreciate it :(
The mean change in muscle thickness observed after a 4-week training regimen was 4 mm, and the 95% confidence interval (CI) for mean change was (-0.5, 8.5). Which is the best scientific conclusion for the effectiveness of this regimen ?
A statistics teacher taught a large introductory statistics class, with 500 students having enrolled over many years. The mean score over all those students on the first midterm was u = 88 with standard deviation o = 10. One year, the teacher taught a %3D much smaller class of only 25 students. The teacher wanted to know if teaching a smaller class was more effective and students performed better. We can consider the small class as an SRS of the students who took the large class over the years. The average midterm score was = 78. The hypothesis should be: a. Ho: H = 78 vs. Ha: H = 88. %3D O b. Ho: µ = 88 vs. Ha: µ 78 %3D Ο d. Ho: μ-88 νs. Ha: μ >88. %3D
The president of a large university wishes to compare the standard deviation of the ages of students presently enrolled to previous years. The distribution of ages has been approximately normal. Find the 90% confidence interval for the population standard deviation of the student ages of the University. A random sample of 20 university students has a standard deviation of 6.1 years in a mean of 23.8 years what is the confidence interval of the population standard deviation?
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Find a 99% confidence interval on the difference in the mean life. Car Brand 1 Brand 2 1 36,925 34,318 2 45,300 42,280 3 36,256 35.548 4 32,100 31,950 5 37,210 38,015 6 48,360 47,800 7 38.200 37,810 8 33,500 33,215 Round your answer to 2 decimal places. Do not use commas.
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It takes an average of 14 minutes for blood to begin clotting after an injury. An EMT wants to see if the average will change if the patient is immediately told the truth about the injury. The EMT randomly selected 43 injured patients to immediately tell the truth about the injury and noticed that they averaged 12.5 minutes for their blood to begin clotting after their injury. Their standard deviation was 3.1 minutes. What can be concluded at the the αα = 0.01 level of significance? For this study, we should use The null and alternative hypotheses would be: H0:H0: H1:H1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 14 at αα = 0.01, so there is statistically significant…
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I chose option 1. I believe that the population mean number of times that adults eat fruit with their breakfast is greater than 3 times. I spoke with 14 adults and found that they had fruit with breakfast 7,2,3,0,0,0,4,7,7,7,4,4,5,and 0 times in the past week. Test this hypothesis at the .05 significance level and assume a random sample.

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