Construct a 90% confidence interval for the variance (standard deviation) of all voltages in the house. Procedure: Select an answer One mean Z procedure One proportion Z procedure One variance χ² procedure One mean T procedure  Assumptions: (select everything that applies) The number of positive and negative responses are both greater than 10 Population standard deviation is unknown Simple random sample Sample size is greater than 30 Population standard deviation is known Normal population Unknown parameter: Select an answer p, population proportion σ², population variance μ, population mean    Point estimate: Select an answer sample mean, x̄ sample variance, s² sample proportion, p̂  = (Round the answer to 3 decimal places) Confidence level % and α=α= , also  α2=α2= , and 1−α2=1-α2=  Critical values: (Round the answer to 3 decimal places) left= right= Margin of error (if applicable):  (Round the answer to 3 decimal places) Lower bound:  (Round the answer to 3 decimal places) Upper bound:  (Round the answer to 3 decimal places) Confidence interval:(, ) Interpretation: We are % confident that the true population variance is between  and . Based on the confidence interval, is it reasonable to believe that the population variance is less than 0.02? Explain. ? No Yes  , because Select an answer a part or the entire interval is above the entire interval is above the entire interval is below a part or the entire interval is below  0.02.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 22SGR
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The proper operation of typical home appliances requires voltage levels that do not vary much. Listed below are 14 voltage levels (in volts) at a random house on 14 different days.

 

120.2 120.1 119.9 119.7 119.9
120 120 120.1 119.8 120.1
120.3 120 120 120  

 

The mean of the data set is 120; the sample standard deviation is 0.15; if the normality plot is not provided you may assume that the voltages are normally distributed.

Construct a 90% confidence interval for the variance (standard deviation) of all voltages in the house.

  1. Procedure: Select an answer One mean Z procedure One proportion Z procedure One variance χ² procedure One mean T procedure 
  2. Assumptions: (select everything that applies)
    • The number of positive and negative responses are both greater than 10
    • Population standard deviation is unknown
    • Simple random sample
    • Sample size is greater than 30
    • Population standard deviation is known
    • Normal population
  3. Unknown parameter: Select an answer p, population proportion σ², population variance μ, population mean   
  4. Point estimate: Select an answer sample mean, x̄ sample variance, s² sample proportion, p̂  = (Round the answer to 3 decimal places)
  5. Confidence level % and α=α= , also
    •  α2=α2= , and 1−α2=1-α2= 
    • Critical values: (Round the answer to 3 decimal places)
      • left= right=
  6. Margin of error (if applicable):  (Round the answer to 3 decimal places)
  7. Lower bound:  (Round the answer to 3 decimal places)
  8. Upper bound:  (Round the answer to 3 decimal places)
  9. Confidence interval:(, )
  10. Interpretation: We are % confident that the true population variance is between  and .
Based on the confidence interval, is it reasonable to believe that the population variance is less than 0.02? Explain.
? No Yes  , because Select an answer a part or the entire interval is above the entire interval is above the entire interval is below a part or the entire interval is below  0.02.
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