The standard deviation of the lengths of hospital stay on the intervention ward is 7.8 days. Complete parts (a) through (c) below. a. For the variable "length of hospital stay." determine the sampling distribution of the sample mean for samples of 66 patients. The standard deviation of the sample mean is a = 9 days. (Round to four decimal places as needed.) b. The distribution of the length of hospital stay is right skewed. Does this invalidate your result in part (a)? Explain your answer. O A. No, because the sample sizes are sufficiently large that x will be approximately normlly distributed, regardless of the distribution of x. B. Yes, because the sample sizes are not sufficiently large that x will be approximately normally distributed, regardless of the distribution of x. OC. No, because if x is normally distributed, then x must be normally distributed. D. Yes, because x is only normally distributed if x is normally distributed. c. Obtain the probability that the sampling error made in estimating the population mean length of stay by the mean length of stay of a sample of 66 patients will be at most 2 days. The probability is approximately 90. (Round to three decimal places as needed.)

The standard deviation of the lengths of hospital stay on the intervention ward is 7.8 days. Complete parts (a) through (c) below. a. For the variable "length of hospital stay." determine the sampling distribution of the sample mean for samples of 66 patients. The standard deviation of the sample mean is a = 9 days. (Round to four decimal places as needed.) b. The distribution of the length of hospital stay is right skewed. Does this invalidate your result in part (a)? Explain your answer. O A. No, because the sample sizes are sufficiently large that x will be approximately normlly distributed, regardless of the distribution of x. B. Yes, because the sample sizes are not sufficiently large that x will be approximately normally distributed, regardless of the distribution of x. OC. No, because if x is normally distributed, then x must be normally distributed. D. Yes, because x is only normally distributed if x is normally distributed. c. Obtain the probability that the sampling error made in estimating the population mean length of stay by the mean length of stay of a sample of 66 patients will be at most 2 days. The probability is approximately 90. (Round to three decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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