Constants | Perindic Table You may want to reference (Pages 168 - 175) section 4.8 while completing this problem. A 34.00 mL sample of an unknown H3PO4 solution is titrated with a 0.110 M NaOH solution. The equivalence point is reached when 25.38 mL of NaOH solution is added. Part A What is the concentration of the unknown H3PO4 solution? The neutralization reaction is H3PO4 (aq) + 3 NAOH(aq) + 3 H20(1) + NazPO4 (aq) ? concentration = M Submit Request Answer

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Exercise 4.88 with feedback
131 of 147
Constants | Periodic Table
You may want to reference (Pages 168 - 175)
section 4.8 while completing this problem.
A 34,00 mL sample of an unknown H3 PO4
solution is titrated with a 0.110 M NAOH solution.
The equivalence point is reached when 25.38 ml,
of NaOH solution is added.
Part A
What is the concentration of the unknown H, PO4 solution? The neutralization reaction is
H3PO4 (aq) + 3NaOH(aq) → 3 H2O(1) + NazPO4 (aq)
concentration =
M
Submit
Request Answer
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Transcribed Image Text:Exercise 4.88 with feedback 131 of 147 Constants | Periodic Table You may want to reference (Pages 168 - 175) section 4.8 while completing this problem. A 34,00 mL sample of an unknown H3 PO4 solution is titrated with a 0.110 M NAOH solution. The equivalence point is reached when 25.38 ml, of NaOH solution is added. Part A What is the concentration of the unknown H, PO4 solution? The neutralization reaction is H3PO4 (aq) + 3NaOH(aq) → 3 H2O(1) + NazPO4 (aq) concentration = M Submit Request Answer Next > Provide Feedback V 10:18 acer
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