Considering Figure FE 2, provide the stress increment at the indicated point of interest due to the concentrated loads, due to the linear load, due to the rectangular load and the final stress increment due to the combination of these loads. Designate your answers using the following variables. “ΔσzCL” - stress increment due to the concentrated loads (bonus) “ΔσzLL” - stress increment due to the linear load (bonus) “ΔσzRL” - stress increment due to the rectangular load (required) “ΔσzT ” - total stress increment at the point of interest (bonus)

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Considering Figure FE 2, provide the stress increment at the indicated point of interest due to the concentrated loads, due to the linear load, due to the rectangular load and the final stress increment due to the combination of these loads. Designate your answers using the following variables. “ΔσzCL” - stress increment due to the concentrated loads (bonus) “ΔσzLL” - stress increment due to the linear load (bonus) “ΔσzRL” - stress increment due to the rectangular load (required) “ΔσzT ” - total stress increment at the point of interest (bonus)
Figure FE 2
IE IE IE 1E IE IE IE E IE
Linear Load, Q = 50 kN/m
Bearing Depth = 0.5 meters below the
ground surface
Rectangular footing, q̟ = 250 kPa
Footing Depth = 1.0 m
%3D
3 m
Concentrated Loads, 80 kN
each; acts 0.5 m below the
ground surface
Point of Interest,
distance from ground
level = 3.5 m
1 m
71m
|13 m
Transcribed Image Text:Figure FE 2 IE IE IE 1E IE IE IE E IE Linear Load, Q = 50 kN/m Bearing Depth = 0.5 meters below the ground surface Rectangular footing, q̟ = 250 kPa Footing Depth = 1.0 m %3D 3 m Concentrated Loads, 80 kN each; acts 0.5 m below the ground surface Point of Interest, distance from ground level = 3.5 m 1 m 71m |13 m
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