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Consider y = (1 + 3x²) Arctan x - 3. what is its derivative? %3D 1 +3x2 1 + x2 A - 6x Arctan x 1 +3x² 1 + x2 6x Arctan x 1 +3x2 1 + x2 + 3x Arctan x 1 +3x2 D 1 + x2 + 6x Arctan x Question 8 3x Evaluate lim ( tan sin - ). A 0 B 2 (c) does not exist B.

Consider y = (1 + 3x²) Arctan x - 3. what is its derivative? %3D 1 +3x2 1 + x2 A - 6x Arctan x 1 +3x² 1 + x2 6x Arctan x 1 +3x2 1 + x2 + 3x Arctan x 1 +3x2 D 1 + x2 + 6x Arctan x Question 8 3x Evaluate lim ( tan sin - ). A 0 B 2 (c) does not exist B.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 7 Consider y = (1 + 3x2) Arctan x -3. What is its derivative? - 1 +3x? 1 + x? (A) 6x Arctan x 1 +3x? (B) 1 + x? 6x Arctan x 1 +3x2 1 + x? (c) + 3x Arctan x - 1 +3x2 (D 1 + x2 + 6x Arctan x Question 8 X 3x Evaluate lim ( tan 4 sin ). A (в) 2 C does not exist D 1
Transcribed Image Text:Question 7 Consider y = (1 + 3x2) Arctan x -3. What is its derivative? - 1 +3x? 1 + x? (A) 6x Arctan x 1 +3x? (B) 1 + x? 6x Arctan x 1 +3x2 1 + x? (c) + 3x Arctan x - 1 +3x2 (D 1 + x2 + 6x Arctan x Question 8 X 3x Evaluate lim ( tan 4 sin ). A (в) 2 C does not exist D 1
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