Consider two algorithms A and B that solve the same class of problems. The time complexity of A is 5000n. The time complexity for B is ceiling(1.1") or 1.1"] Find the time required to execute each for n=10, n=100, n= 1000, n=1000000 Tabulate your results? which algorithm has better performance for n>1000 Exercise 2: Find an upper bound and a lower bound for each of the function f(x). 1) f(x)=x²+2x+1.
Consider two algorithms A and B that solve the same class of problems. The time complexity of A is 5000n. The time complexity for B is ceiling(1.1") or 1.1"] Find the time required to execute each for n=10, n=100, n= 1000, n=1000000 Tabulate your results? which algorithm has better performance for n>1000 Exercise 2: Find an upper bound and a lower bound for each of the function f(x). 1) f(x)=x²+2x+1.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Hello, can you please help me do exercise 3 (with subparts 1,2,3, and 4)?
Thank you so much!

Transcribed Image Text:Exercise 1:
Consider two algorithms A and B that solve the same class of problems.
The time complexity of A is 5000n. The time complexity for B is ceiling(1.1) or 1.17
Find the time required to execute each for n=10, n=100, n= 1000, n=1000000
Tabulate your results? which algorithm has better performance for n>1000
Exercise 2:
Find an upper bound and a lower bound for each of the function f(x).
f(x)=x²+2x+1.
1)
2) f(x)= 3x²+2x² + x
3) f(n)-(6n+4)(1+lg n)
Exercise 3:
Consider the algorithm below:
1. ien;
2. while (i z1) {
3. x=x+1
4. i=i/2}
Trace the algorithm, and fill the table that indicates the number of times x=x+1 for the following
values of n
n
8
16
32
i (range)
(8,4,2,1)
#times x=x+1 executed
4
Find a theta notation in terms of n for the number of times the statement x-x+1 is executed based on
generalizing the results above for n=2". Note that if n=2", then k=log2 (n).
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