Consider this isomerization reaction between cyclopropane (C) and propene (P) This is a first order reaction, so its rate law is given by: Rate = - change[C]/ change time = k(C) The rate constant, k, is equal to 9.20 s-1. (a) If [C]o = 6.00 M, what is the concentration after 1.00 (b) If [C]o = 6.00 M, at what time will the concentration fall to a value of 0.15 M? For this part, you will have to use the equation ln [C] = -k t and solve it for t in seconds. [C]o c) What is the half life of this reaction?
Consider this isomerization reaction between cyclopropane (C) and propene (P)
This is a first order reaction, so its rate law is given by:
Rate = - change[C]/ change time = k(C)
The rate constant, k, is equal to 9.20 s-1.
(a) If [C]o = 6.00 M, what is the concentration after 1.00
(b) If [C]o = 6.00 M, at what time will the concentration fall to a value of 0.15 M?
For this part, you will have to use the equation
ln [C] = -k t and solve it for t in seconds.
[C]o
c) What is the half life of this reaction?
d.) If the initial concentration of cyclopropane is 10.0 M, when will the concentration of cyclopropane fall to 1.25 M?
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