Consider these reactions, where M represents a generic metal. 2 M(s) + 6HCl(aq). 2MCl3(aq) + 3H₂(g) HCl(g) → HCl(aq) H₂(g) + Cl2₂(g) →→→ 2 HCl(g) MC13 (s) →→→ MC1₂(aq) Use the given reactions to determine the enthalpy of the following reaction. 2M(s) + 3 Cl₂(g) 2 MC13 (s) 1. 2. 3. 4. Step 2: Identify how the enthalpies of the individual reactions are affected after the equations are manípulated. AH₁ adjusted for direction and factor: AH3 adjusted for direction and factor: -724 AH2 adjusted for direction and factor: -448.8 AH4 adjusted for direction and factor: Incorrect -5535 640 AH₁-887.0 kJ AH₂ = -74.8 kJ AH3-1845.0 kJ AHA-415.0 kJ Incorrect k k k k
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
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![Consider these reactions, where M represents a generic metal.
2 M(s) + 6HCl(aq)
2MC13(aq) + 3H₂(g)
HCl(g) → HCl(aq)
H₂(g) + Cl₂(g) -
MC1₂ (s)
MC1₂ (aq)
Use the given reactions to determine the enthalpy of the following reaction.
2M(s) + 3 Cl₂(g) → 2 MC1₂ (s)
1.
2.
3.
4.
2 HCl(g)
AH₁ adjusted for direction and factor:
Step 2: Identify how the enthalpies of the individual reactions are affected after the equations are manípulated.
-724
Incorrect
AH2 adjusted for direction and factor: -448.8
AH4 adjusted for direction and factor:
AH3 adjusted for direction and factor: -5535
640
AH₁-887.0 kJ
AH₂ = -74.8 kJ
Incorrect
AH3-1845.0 kJ
AHA-415.0 kJ
kJ
kJ
kJ
kJ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9abfb68-8e72-4551-93ea-7c2837d5dcac%2Ffa22efe8-325a-4a7d-853a-7eefe82de286%2F2ilnce_processed.png&w=3840&q=75)
![Step 3: Determine the enthalpy of the overall reaction from the adjusted enthalpies of the individual reactions.
AH =
-3657
Incorrect
kJ](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9abfb68-8e72-4551-93ea-7c2837d5dcac%2Ffa22efe8-325a-4a7d-853a-7eefe82de286%2Fmccqwur_processed.png&w=3840&q=75)
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