Consider these 1669 people to be a population. Let Xbe the number of hours of relaxation for a person sampled at random from this population. X 1 2 3 4 5 6 7 8 P(x) Find the probability that a person relaxes more than 4hours per day. Find the probability that a person doesn't relax at all. Round the answer to three decimal places.) Compute the mean .Compute the mean Round the answer to two decimal places. Compute the standard deviation Round the answer to three decimal place
Consider these 1669 people to be a population. Let Xbe the number of hours of relaxation for a person sampled at random from this population. X 1 2 3 4 5 6 7 8 P(x) Find the probability that a person relaxes more than 4hours per day. Find the probability that a person doesn't relax at all. Round the answer to three decimal places.) Compute the mean .Compute the mean Round the answer to two decimal places. Compute the standard deviation Round the answer to three decimal place
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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100%
Dirty air: The federal government has enacted maximum allowable standards for air pollutants such as ozone. Let X be the number of days per year that the level of air pollution exceeds the standard in a certain city. The
|
X 0 1 2 3 4
P(x) 0.35 0.38 0.91 0.05 0.03
- Find p(1) Find (2 or fewer) c.Find the probability that the standard is exceeded on at least one day.
- Find the probability that the standard is exceeded on more than one day
- Compute the mean . Round the answer to two decimal places.
- (f) Compute the standard deviation . Round the answer to three decimal places.
- Relax! A recent survey asked people how many hours per day they were able to relax. The results are presented in the following table.
Number of Hours |
Frequency |
0.112
-
-
-
- 185
- 336
- 249
- 315
- 229
- 150
- 33
- 60
-
-
Total 1669
2. Consider these 1669 people to be a population. Let Xbe the number of hours of relaxation for a person sampled at random from this population.
- X 1 2 3 4 5 6 7 8
P(x)
- Find the probability that a person relaxes more than 4hours per day.
- Find the probability that a person doesn't relax at all. Round the answer to three decimal places.)
- Compute the mean
- .Compute the mean Round the answer to two decimal places.
Compute the standard deviation Round the answer to three decimal places
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