Consider the two signals c₁(t) = 4 cos(50000πt) and c₂(t) = 4 sin(50000πt). The real and the imaginary parts of the spectrum of two signals, m₁(t) and m²(t), are shown in the following figure. M₁(f) M₂(f) Re Im -5000 M₁(f) -5000 10 5000 f-> 0 5000 f-> -5000 M₂(f) -5000 To 5000 f 5000 1) Draw the real and the imaginary parts of the spectrum of z(t) = m₁(t)c₁(t) + m₂(t)c₂(t). 2) Draw the real and the imaginary parts of the spectrum of w(t) = m₁(t)c₁(t) — m₂ (t)c₂(t). 3) If z(t) is multiplied by c₂(t), then integrated (or equivalently, passed through a LPF), what will be the output signal? 4) If w(t) is multiplied by c₂ (t), then integrated (or equivalently, passed through a LPF), what will be the output signal?
Consider the two signals c₁(t) = 4 cos(50000πt) and c₂(t) = 4 sin(50000πt). The real and the imaginary parts of the spectrum of two signals, m₁(t) and m²(t), are shown in the following figure. M₁(f) M₂(f) Re Im -5000 M₁(f) -5000 10 5000 f-> 0 5000 f-> -5000 M₂(f) -5000 To 5000 f 5000 1) Draw the real and the imaginary parts of the spectrum of z(t) = m₁(t)c₁(t) + m₂(t)c₂(t). 2) Draw the real and the imaginary parts of the spectrum of w(t) = m₁(t)c₁(t) — m₂ (t)c₂(t). 3) If z(t) is multiplied by c₂(t), then integrated (or equivalently, passed through a LPF), what will be the output signal? 4) If w(t) is multiplied by c₂ (t), then integrated (or equivalently, passed through a LPF), what will be the output signal?
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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As per bartleby's guidelines you are required apparently to answer 3 parts only so I want you to answer 2,3,4 only.
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Step 1: what is given and what is required:
VIEWStep 2: Part (i)-Finding real and imaginary parts of the spectrums of z(t):
VIEWStep 3: Part (ii)-Finding real and imaginary parts of the spectrums of w(t):
VIEWStep 4: Part (iii)- If z(t) is multiplied by c2(t) and then the product is passed by LPF:
VIEWStep 5: Part (iv)- If w(t) is multiplied by c2(t) and then the product is passed by LPF:
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