Consider the two planes (5x+y-z=0) and (x-2y+3z=-1) Argue why the intersection of these two planes is a curve; i.e. the intersection is one dimensional?
Consider the two planes (5x+y-z=0) and (x-2y+3z=-1) Argue why the intersection of these two planes is a curve; i.e. the intersection is one dimensional?
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Consider the two planes (5x+y-z=0) and (x-2y+3z=-1)
Argue why the intersection of these two planes is a curve; i.e. the
intersection is one dimensional?
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