Consider the titration of 25.0 mt. of 0.070 M HCN with 0.080 H NaOH, what volume of base, in matters, is required to reach the equivalence point? Volume-21.871 m The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus n(HCN) = n(NaOH) [HCN] × V(HCN)-[NaOH] × V(NaOH) V(NaOH)-22 mL Consider the titration of 25.0 ml of 0.070 M HCN (K, -4.0 x 10) with 0.080 M NaOH. what is the pH before any NaOH is added? pH initial- what is the pH at the halfway point of the titration? pH at halfway- What is the pet when 95% of the NaOH required to reach the equivalence point has been added pH when 95% is added- What is the pit at the equivalence point? pet at the equivalence point- Correct Submit
Consider the titration of 25.0 mt. of 0.070 M HCN with 0.080 H NaOH, what volume of base, in matters, is required to reach the equivalence point? Volume-21.871 m The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus n(HCN) = n(NaOH) [HCN] × V(HCN)-[NaOH] × V(NaOH) V(NaOH)-22 mL Consider the titration of 25.0 ml of 0.070 M HCN (K, -4.0 x 10) with 0.080 M NaOH. what is the pH before any NaOH is added? pH initial- what is the pH at the halfway point of the titration? pH at halfway- What is the pet when 95% of the NaOH required to reach the equivalence point has been added pH when 95% is added- What is the pit at the equivalence point? pet at the equivalence point- Correct Submit
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 110QRT: Consider the nanoscale-level representations for Question 110 of the titration of the aqueous weak...
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![bconsider the titration of 25.0 ml. of 0.070 M HCN with 0.080 M NaOH. What volume of base, in milliliters, is required to reach the equivalence point?
Volume 21.87✔ mL
The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus
n(HCN) n(NaOH)
[HCN] × V(HCN)= [NaOH] × V(NaOH)
V(NaOH)22 mL
Consider the titration of 25,0 ml of 0.070 M HCN (K, 4.0 x 10-10) with 0.080 M NaOH.
What is the pH before any NaOH is added?
pH initial
what is the pH at the halfway point of the titration?
pit at halfway-
What is the pH when 95% of the NaOH required to reach the equivalence point has been added
pH when 95% is added-
What is the pH at the equivalence point?
pet at the equivalence point-
Correct
Submit](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe290f887-b5df-40df-82d0-665473d14543%2Fee8bf985-93f0-41b5-9fda-b276d6df3cfc%2Fpqvhdxs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:bconsider the titration of 25.0 ml. of 0.070 M HCN with 0.080 M NaOH. What volume of base, in milliliters, is required to reach the equivalence point?
Volume 21.87✔ mL
The equivalence point for a reaction is the point at which one reactant has been completely consumed by addition of another reactant. Thus
n(HCN) n(NaOH)
[HCN] × V(HCN)= [NaOH] × V(NaOH)
V(NaOH)22 mL
Consider the titration of 25,0 ml of 0.070 M HCN (K, 4.0 x 10-10) with 0.080 M NaOH.
What is the pH before any NaOH is added?
pH initial
what is the pH at the halfway point of the titration?
pit at halfway-
What is the pH when 95% of the NaOH required to reach the equivalence point has been added
pH when 95% is added-
What is the pH at the equivalence point?
pet at the equivalence point-
Correct
Submit
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