Consider the system of differential equations Verify that z' = [( 1] ², 2(0) = | ¹0+ z(t) = c₁e¹t + c₂e 2¹ [¹] is a solution to the system of differential equations for any choice of the constants c₁ and c₂. Find values of c₁ and c₂ that solve the given initial value problem. (According to the uniqueness theorem, you have found the unique solution of ' =P*, (0) = o). z (t) = De]+( 4).e-2 [1]. help (numbers)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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4. Ordinary Differential Equations

### System of Differential Equations

Consider the following system of differential equations:

\[
\vec{x}' = \begin{bmatrix} 1 & 3 \\ 3 & 1 \end{bmatrix} \vec{x}, \quad \vec{x}(0) = \begin{bmatrix} -12 \\ -2 \end{bmatrix}.
\]

### Verification Task

Verify that 

\[
\vec{x}(t) = c_1 e^{4t} \begin{bmatrix} 1 \\ 1 \end{bmatrix} + c_2 e^{-2t} \begin{bmatrix} 1 \\ -1 \end{bmatrix}
\]

is a solution to the system of differential equations for any choice of the constants \( c_1 \) and \( c_2 \).

### Initial Value Problem

Find the values of \( c_1 \) and \( c_2 \) that solve the given initial value problem 
with \(\vec{x} = P\vec{x}, \quad \vec{x}(0) = \vec{x}_0\).

According to the uniqueness theorem, you will find the unique solution.

\[
\vec{x}(t) = \left(\begin{bmatrix} \, \, \, \, \, \end{bmatrix} \right) \cdot e^{4t} \begin{bmatrix} 1 \\ 1 \end{bmatrix} + \left(\begin{bmatrix} \, \, \, \, \, \end{bmatrix} \right) \cdot e^{-2t} \begin{bmatrix} 1 \\ -1 \end{bmatrix}. 
\]

For assistance, use the following [help (numbers)].

---

This text aims to guide learners through solving a system of differential equations using initial conditions to find specific constants. The solution involves determining \(c_1\) and \(c_2\) based on the initial vector and analyzing the exponential terms as projected onto the eigenvectors of the system matrix.
Transcribed Image Text:### System of Differential Equations Consider the following system of differential equations: \[ \vec{x}' = \begin{bmatrix} 1 & 3 \\ 3 & 1 \end{bmatrix} \vec{x}, \quad \vec{x}(0) = \begin{bmatrix} -12 \\ -2 \end{bmatrix}. \] ### Verification Task Verify that \[ \vec{x}(t) = c_1 e^{4t} \begin{bmatrix} 1 \\ 1 \end{bmatrix} + c_2 e^{-2t} \begin{bmatrix} 1 \\ -1 \end{bmatrix} \] is a solution to the system of differential equations for any choice of the constants \( c_1 \) and \( c_2 \). ### Initial Value Problem Find the values of \( c_1 \) and \( c_2 \) that solve the given initial value problem with \(\vec{x} = P\vec{x}, \quad \vec{x}(0) = \vec{x}_0\). According to the uniqueness theorem, you will find the unique solution. \[ \vec{x}(t) = \left(\begin{bmatrix} \, \, \, \, \, \end{bmatrix} \right) \cdot e^{4t} \begin{bmatrix} 1 \\ 1 \end{bmatrix} + \left(\begin{bmatrix} \, \, \, \, \, \end{bmatrix} \right) \cdot e^{-2t} \begin{bmatrix} 1 \\ -1 \end{bmatrix}. \] For assistance, use the following [help (numbers)]. --- This text aims to guide learners through solving a system of differential equations using initial conditions to find specific constants. The solution involves determining \(c_1\) and \(c_2\) based on the initial vector and analyzing the exponential terms as projected onto the eigenvectors of the system matrix.
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