Consider the series Σ n=1 1 n³ + 7n Write an inequality comparing inequality: Incorrect 1 n³ + 7n (Express numbers in exact form. Use symbolic notation and fractions where needed.) 1 ∞ Draw a conclusion about Σ ∞ and Σ n=1 1 1 n3/2 1 n=1 √n³ +7n − 1 to 1 n312 for n ≥ 1. The series converges by the Direct Comparison Test since 1 It is not possible to draw a conclusion based on this information. n³/2 converges. The series diverges by the Direct Comparison Test since 1 diverges. 1 n3/2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the series
1
Ë
n=1 √√√n³ +7n−1
Write an inequality comparing
inequality:
1
n³ +7n - 1
(Express numbers in exact form. Use symbolic notation and fractions where needed.)
Incorrect
1
and 2 =
n=1
∞
Draw a conclusion about Σ
n=1
n3/2
1
/n³ +7n - 1
to
1
n3/2
for n ≥ 1.
1
n³/2
The series converges by the Direct Comparison Test since Σ1 converges.
It is not possible to draw a conclusion based on this information.
The series diverges by the Direct Comparison Test since Σ1 diverges.
1
n³12
Transcribed Image Text:Consider the series 1 Ë n=1 √√√n³ +7n−1 Write an inequality comparing inequality: 1 n³ +7n - 1 (Express numbers in exact form. Use symbolic notation and fractions where needed.) Incorrect 1 and 2 = n=1 ∞ Draw a conclusion about Σ n=1 n3/2 1 /n³ +7n - 1 to 1 n3/2 for n ≥ 1. 1 n³/2 The series converges by the Direct Comparison Test since Σ1 converges. It is not possible to draw a conclusion based on this information. The series diverges by the Direct Comparison Test since Σ1 diverges. 1 n³12
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