Consider the sequence in figure below, Assuming that fs=100 Hz, compute the amplitude spectrum, phase spectrum, and power spectrum. X(2)=-2 Y(3)=-2-j2 x(n) 4 3+ 2+ 1+ 0 2 1 TNT Similarly, for k= 3, f = Solution:- Since N=4, and using the DFT shown in example 4.1. we find the DFT coefficients to be X(0)=10 X(1)=-2+j2 for k= 1, f = 1 x 100/4 = 25 Hz, Solution: Since N= 4, and using the DFT shown in Example 4.1, we find the DFT coefficients to be X(0) 10 X(1) = -2+12 X(2) = -2 X(3)=-2-12 The amplitude spectrum, phase spectrum, and power density spectrum are computed as follows: for k= 0, f = kfs/N = 0 x 100/4 = 0 Hz, A = 1X (0)| = 2.5, %0 = tan-¹ for k= 2, f= 2 x 100/4= 50 Hz, A₁ = X(1)| = 0.7071, ₁ = tan-1 A2 = X(2)| = 0.5, 02 = tan 3 3 x 100/4 = 75 Hz, A3 = 1X (3)| = 0.7071, 43 Imag[X(0)] Real(X(0)] 5 an -1/Imag[X(2)] eal X(2) n -1 (Imag{X (1)]) Real | = 0, Po = AXIO) = 6.25 (Imag[X(3)]) Real X(3) = 1350, P₁= X(1)² = 0.5 = 0.5000 = 180°, P₂=X(2) ²0 0.2500 = -1350 P3=2X(3) 1² = 0.5000.

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How were atan outputs calculated

Consider the sequence in figure below, Assuming that fs=100 Hz, compute the
amplitude spectrum, phase spectrum, and power spectrum.
x(n)
3
2
X(0) = 10
X(1) = -2+12
X(2) = -2
X(3)=-2-12
1
0
T = NT
Solution:-
Since N=4, and using the DFT shown in example 4.1. we find the DFT coefficients to be
X(0)=10
X(1)=-2+j2
X(2)=-2
Y(3)=-2-j2
A₂ = X(2)| = 0.5, 02 = tan
1
Solution:
Since N 4, and using the DFT shown in Example 4.1, we find the DFT coefficients to be
Similarly,
for k= 3, f= 3 x 100/4 = 75 Hz,
4
A3 = X(3)| = 0.7071, 43
H
The amplitude spectrum, phase spectrum, and power density spectrum are computed as follows:
for k= 0, f = kfs/N = 0 x 100/4 = 0 Hz,
A = 1X (0)| = 2.5, %= tan-1
Imag[X(0)]
Real([X(0)
an
for k= 1, f 1 x 100/4 = 25 Hz,
A₁ = X(1)| = 0.7071, ₁ = tan-1 (Imag(X(1)]) = 135⁰, P₁= X(1)² = 0.5000
Real X(1)])
for k= 2, f = 2 x 100/4 = 50 Hz,
-1
5
Imag[X(2)])
eal X(2)
n
| = 0, Po = AX(0)2 = 6.25
Imag[X(3)]
Real X(3)]
= 180°, P₂ = x(2)² = 0
0.2500
=-1350 P3 = X(3)1²=0.5000.
"dy
Transcribed Image Text:Consider the sequence in figure below, Assuming that fs=100 Hz, compute the amplitude spectrum, phase spectrum, and power spectrum. x(n) 3 2 X(0) = 10 X(1) = -2+12 X(2) = -2 X(3)=-2-12 1 0 T = NT Solution:- Since N=4, and using the DFT shown in example 4.1. we find the DFT coefficients to be X(0)=10 X(1)=-2+j2 X(2)=-2 Y(3)=-2-j2 A₂ = X(2)| = 0.5, 02 = tan 1 Solution: Since N 4, and using the DFT shown in Example 4.1, we find the DFT coefficients to be Similarly, for k= 3, f= 3 x 100/4 = 75 Hz, 4 A3 = X(3)| = 0.7071, 43 H The amplitude spectrum, phase spectrum, and power density spectrum are computed as follows: for k= 0, f = kfs/N = 0 x 100/4 = 0 Hz, A = 1X (0)| = 2.5, %= tan-1 Imag[X(0)] Real([X(0) an for k= 1, f 1 x 100/4 = 25 Hz, A₁ = X(1)| = 0.7071, ₁ = tan-1 (Imag(X(1)]) = 135⁰, P₁= X(1)² = 0.5000 Real X(1)]) for k= 2, f = 2 x 100/4 = 50 Hz, -1 5 Imag[X(2)]) eal X(2) n | = 0, Po = AX(0)2 = 6.25 Imag[X(3)] Real X(3)] = 180°, P₂ = x(2)² = 0 0.2500 =-1350 P3 = X(3)1²=0.5000. "dy
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