Consider the reaction of ethyl bromide with sodium hydroxide: CH3 CH2B1(aq)+ NaOH(aq) = CH;CH2OH(aq) + NaBr(aq) The reaction is first order in NaOH and second order overall. What is the rate law? • View Available Hint(s) O rate : k[CH3 CH2 Br] [NaOH O rate= ] k[CH3 CH2 Br|[NaOH rate = k[NaOH] O rate = k[CH3CH,Br] |3D O rate = k(CH3 CH,Br||NaOH O rate = k[CH3CH,Br INAOH] %3D
Consider the reaction of ethyl bromide with sodium hydroxide: CH3 CH2B1(aq)+ NaOH(aq) = CH;CH2OH(aq) + NaBr(aq) The reaction is first order in NaOH and second order overall. What is the rate law? • View Available Hint(s) O rate : k[CH3 CH2 Br] [NaOH O rate= ] k[CH3 CH2 Br|[NaOH rate = k[NaOH] O rate = k[CH3CH,Br] |3D O rate = k(CH3 CH,Br||NaOH O rate = k[CH3CH,Br INAOH] %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Part A
Consider the reaction of ethyl bromide with sodium hydroxide:
CH3 CH2B1(aq) + NaOH(aq) = CH3CH2OH(aq) + NaBr(aq)
The reaction is first order in NaOH and second order overall. What is the rate law?
• View Available Hint(s)
O rate = k[CH3 CH,Br] [NaOH]²
O rate = k[CH3 CH,Br]NAOH]²
O rate = k[N2OH]
O rate =
k[CH3CH,Br]
rate = k(CH3 CH2B1]NAOH]
O rate = k(CH3 CH,Br] NaOH]
Submit](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c6de790-3967-4822-b83d-f877aa472903%2Fd0ddf06e-4b88-4534-80e0-021be57f8707%2Fy0xvre_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part A
Consider the reaction of ethyl bromide with sodium hydroxide:
CH3 CH2B1(aq) + NaOH(aq) = CH3CH2OH(aq) + NaBr(aq)
The reaction is first order in NaOH and second order overall. What is the rate law?
• View Available Hint(s)
O rate = k[CH3 CH,Br] [NaOH]²
O rate = k[CH3 CH,Br]NAOH]²
O rate = k[N2OH]
O rate =
k[CH3CH,Br]
rate = k(CH3 CH2B1]NAOH]
O rate = k(CH3 CH,Br] NaOH]
Submit
![The rate of a chemical reaction depends on the
concentrations of the reactants. Let's consider the
general reaction between A and B:
aA + bB = cC + dD
The dependence of the reaction rate on the
concentration of each reactant is given by the
equation called the rate law.
n
rate = k[A]" [B]"
where k is a proportionality constant called the rate
constant. The exponent m determines the reaction
order with respect to A, and n determines the
reaction order with respect to B. The overall
reaction order equals the sum of the exponents (
m+n).
For example, if m = 2 andn=2 then
rate = k[A]2 B]² and the overall reaction order is
2+2=4.
The reaction orders are experimentally determined
and usually not related to the reaction
stoichiometric coefficients a and b.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c6de790-3967-4822-b83d-f877aa472903%2Fd0ddf06e-4b88-4534-80e0-021be57f8707%2Fp1zq37q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The rate of a chemical reaction depends on the
concentrations of the reactants. Let's consider the
general reaction between A and B:
aA + bB = cC + dD
The dependence of the reaction rate on the
concentration of each reactant is given by the
equation called the rate law.
n
rate = k[A]" [B]"
where k is a proportionality constant called the rate
constant. The exponent m determines the reaction
order with respect to A, and n determines the
reaction order with respect to B. The overall
reaction order equals the sum of the exponents (
m+n).
For example, if m = 2 andn=2 then
rate = k[A]2 B]² and the overall reaction order is
2+2=4.
The reaction orders are experimentally determined
and usually not related to the reaction
stoichiometric coefficients a and b.
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