Consider the reaction:B40,2- + 14H* + 12e = 4B(s) + 7H2OThe Nernst equation for this reaction isE = -0.792 - (0.05916/n)log(x/y)n =||For x and y, write only the letter corresponding to your answerа. 1b. 4с. 7d. 12е. 14f. [ B ]4g. [H* ]14[ e¯ ]12h. [ B40,2- ][ e¯ ]14i. [ B40,2- ][ H* ]14j. [ B40,2- ][ H* ]14[ e¯ ]12X =y =

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Consider the reaction: B40,2- + 14H* + 12e = 4B(s) + 7H2O The Nernst equation for this reaction is E = -0.792 - (0.05916/n)log(x/y) | For x and y, write only the letter corresponding to your answer а. 1 b. 4 с. 7 d. 12 е. 14 f. [ B ]ª g. [H* ]14[ e¯ ]12 h. [ B40,2- ][ e¯ ]14 i. [ B40,2- ][ H* ]14 j. [ B40,2- ][ H* ]14[ e¯ ]12 X = y =

Consider the reaction: B40,2- + 14H* + 12e = 4B(s) + 7H2O The Nernst equation for this reaction is E = -0.792 - (0.05916/n)log(x/y) | For x and y, write only the letter corresponding to your answer а. 1 b. 4 с. 7 d. 12 е. 14 f. [ B ]ª g. [H* ]14[ e¯ ]12 h. [ B40,2- ][ e¯ ]14 i. [ B40,2- ][ H* ]14 j. [ B40,2- ][ H* ]14[ e¯ ]12 X = y =

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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