Consider the PV diagram of system of a 1.4-mole H₂ gas (Cv = 5R/2, Cp = 7R/2). Pressure [Pa] 115000 110 000 105 000 100 000 95 000 0.024 (0.0250, 113016) (0.0250, 96396) TA = 290K 0.026 TB= (0.0294, 113016) = 340K 0.028 Volume [m³] Tc = 400K 0.030 0.032
Consider the PV diagram of system of a 1.4-mole H₂ gas (Cv = 5R/2, Cp = 7R/2). Pressure [Pa] 115000 110 000 105 000 100 000 95 000 0.024 (0.0250, 113016) (0.0250, 96396) TA = 290K 0.026 TB= (0.0294, 113016) = 340K 0.028 Volume [m³] Tc = 400K 0.030 0.032
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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![Consider the PV diagram of system of a 1.4-mole H₂ gas (Cv = 5R/2, Cp = 7R/2).
Pressure [Pa]
115 000
110 000
105 000
100 000
95 000
(0.0250, 113016)
0.024
(0.0250, 96396)
T₁ = 290K
0.026
(0.0294, 113016)
TB = 340K
Тв
Tc = 400K
0.028
Volume [m³]
What is the net change in internal energy of the gas after one complete cycle? Express your answer in Joules and with two decimal places.
0.030
0.032](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbd37601c-9475-4fbf-b8e6-34bf9324a7c1%2F238a8c99-f25b-48f3-aa3a-4633f24f136d%2Ff2dlxg9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the PV diagram of system of a 1.4-mole H₂ gas (Cv = 5R/2, Cp = 7R/2).
Pressure [Pa]
115 000
110 000
105 000
100 000
95 000
(0.0250, 113016)
0.024
(0.0250, 96396)
T₁ = 290K
0.026
(0.0294, 113016)
TB = 340K
Тв
Tc = 400K
0.028
Volume [m³]
What is the net change in internal energy of the gas after one complete cycle? Express your answer in Joules and with two decimal places.
0.030
0.032
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