Consider the physical quantities s, t, u, v and w. We would like to work with these quantitiesusing Buckingham's theorem. The dimensions of these quantities are:[s] = MLT-1[t] = T-1[u] = MT²3[v] = [³[w] = MWe find dimensionless products of the form[s]ª[t]b[u][v]d[w]eand choose a and c as arbitrary variables.One of the dimensionless products that we arrive at does not contain v at all. In thatdimensionless product, the exponent of t is:(If t occurs in the denominator, please write the exponent as a negative number.)

Here we have to make a formulation of the given quantities in the mathematical model. So, we…

Consider the physical quantities s, t, u, v and w. We would like to work with these quantities using Buckingham's theorem. The dimensions of these quantities are: [s] = MLT-1 [t] =T-¹ [u]=MT² [v]=1³ [w] = M We find dimensionless products of the form [s]a[t][u][v] [w] and choose a and c as arbitrary variables. One of the dimensionless products that we arrive at does not contain v at all. In that dimensionless product, the exponent of t is: (If t occurs in the denominator, please write the exponent as a negative number.)

Consider the physical quantities s, t, u, v and w. We would like to work with these quantities using Buckingham's theorem. The dimensions of these quantities are: [s] = MLT-1 [t] =T-¹ [u]=MT² [v]=1³ [w] = M We find dimensionless products of the form [s]a[t][u][v] [w] and choose a and c as arbitrary variables. One of the dimensionless products that we arrive at does not contain v at all. In that dimensionless product, the exponent of t is: (If t occurs in the denominator, please write the exponent as a negative number.)