Consider the molecules. Classify the molecules as constitutional isomers, enantiomers, the same compound, or not isomers. НО Н -- OH Н HO Н OH

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**Question 14 of 30**

**Consider the molecules. Classify the molecules as constitutional isomers, enantiomers, the same compound, or not isomers.**

The given molecules are:

1. The first molecule has the following structure:
   - A central carbon (C) atom bonded to four groups:
     - A hydroxyl group (HO) indicated with a solid wedge.
     - A hydrogen atom (H) positioned below the plane.
     - A methyl group (CH2) leading to a hydroxyl group (OH).
     - An adjacent hydrogen atom (H) on the central carbon atom.

2. The second molecule has the following structure:
   - A central carbon (C) atom bonded similarly to four groups:
     - A hydroxyl group (HO) indicated with a solid wedge.
     - A hydrogen atom (H) positioned below the plane (opposite orientation to the first molecule).
     - A methyl group (CH2) leading to a carbonyl group (C=O).
     - An adjacent hydrogen atom (H) on the central carbon atom.

**The classification options are:**

1. Constitutional Isomers
2. Not Isomers
3. Same Compound
4. Enantiomers

**Explanation of Options:**

- **Constitutional Isomers** refer to molecules with the same molecular formula but different connectivity of atoms within the molecule.
- **Not Isomers** means the molecules do not share a significant relationship in structure or composition.
- **Same Compound** implies both molecules are identical in both structure and physical properties.
- **Enantiomers** are a pair of molecules that are non-superimposable mirror images of each other.

**Graphical Representation:**

The image depicts two molecular structures side by side for comparison, aiding in understanding their spatial arrangement and connectivity for categorization.
 
**Analysis:**

- Check the connectivity and arrangements for constitutional isomers.
- Compare the spatial orientation of molecules for enantiomers.

Lastly, select the most accurate class based on the provided options after detailed molecular comparison.
Transcribed Image Text:**Question 14 of 30** **Consider the molecules. Classify the molecules as constitutional isomers, enantiomers, the same compound, or not isomers.** The given molecules are: 1. The first molecule has the following structure: - A central carbon (C) atom bonded to four groups: - A hydroxyl group (HO) indicated with a solid wedge. - A hydrogen atom (H) positioned below the plane. - A methyl group (CH2) leading to a hydroxyl group (OH). - An adjacent hydrogen atom (H) on the central carbon atom. 2. The second molecule has the following structure: - A central carbon (C) atom bonded similarly to four groups: - A hydroxyl group (HO) indicated with a solid wedge. - A hydrogen atom (H) positioned below the plane (opposite orientation to the first molecule). - A methyl group (CH2) leading to a carbonyl group (C=O). - An adjacent hydrogen atom (H) on the central carbon atom. **The classification options are:** 1. Constitutional Isomers 2. Not Isomers 3. Same Compound 4. Enantiomers **Explanation of Options:** - **Constitutional Isomers** refer to molecules with the same molecular formula but different connectivity of atoms within the molecule. - **Not Isomers** means the molecules do not share a significant relationship in structure or composition. - **Same Compound** implies both molecules are identical in both structure and physical properties. - **Enantiomers** are a pair of molecules that are non-superimposable mirror images of each other. **Graphical Representation:** The image depicts two molecular structures side by side for comparison, aiding in understanding their spatial arrangement and connectivity for categorization. **Analysis:** - Check the connectivity and arrangements for constitutional isomers. - Compare the spatial orientation of molecules for enantiomers. Lastly, select the most accurate class based on the provided options after detailed molecular comparison.
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