Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGs = 42000 km. Consider the mechanical energy of the same body on Earth at the South pole, atr. = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.) G = 6.67 x 10-11 Nm2kg2, and the mass of the Earth is M = 5.97 x 1024 kg What is the difference in the mechanical energy per kilogram between the two? E = MJ.kg (to two significant figures, don't use scientific notation)
Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGs = 42000 km. Consider the mechanical energy of the same body on Earth at the South pole, atr. = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the object at the equator is in orbit, the object at the Pole is not in orbit.) G = 6.67 x 10-11 Nm2kg2, and the mass of the Earth is M = 5.97 x 1024 kg What is the difference in the mechanical energy per kilogram between the two? E = MJ.kg (to two significant figures, don't use scientific notation)
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Transcribed Image Text:Consider the mechanical energy of a body in geostationary orbit above the Earth's equator, at rGS = 42000 km.
Consider the mechanical energy of the same body on Earth at the South pole, at re = 6400 km. For this problem, we consider the Earth to be spherical. (Remember, the
object at the equator is in orbit, the object at the Pole is not in orbit.)
G = 6.67 x 10-11 Nm²kg-2, and the mass of the Earth is M = 5.97 x 1024 kg
What is the difference in the mechanical energy per kilogram between the two?
E =_ MJ.kg (to two significant figures, don't use scientific notation)
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