Consider the matrices [1 0 0 1 -5 0 -3 R= |0 0 0 0 0 0 1 -3 17 -1 9. 3 2 -6 4 12 A = |3 -1 11 4 24 and 1 3 4 8 1 15 10 1 18 You may assume that R is the reduced echelon form (RREF) of A. (a) Find a basis for the column space col(A). You must justify your answer. (b) Find a basis for the null space null(A). You must justify your answer. (c) What is the rank of A, that is, the dimension of col(A)? No justification necessary. (d) What is the nullity of A, that is, the dimension of null(A)? No justification necessary.

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Consider the matrices
-3
17
-1
9.
[1 0
3
-6
4
12
1
-5 0
-3
A =
3
-1
11
4
24
and
R =
0 0
1
3
0 0
0 0
4
8
1
15
10
1
18
You may assume that R is the reduced echelon form (RREF) of A.
(a) Find a basis for the column space col(A). You must justify your answer.
(b) Find a basis for the null space null(A). You must justify your answer.
(c) What is the rank of A, that is, the dimension of col(A)? No justification necessary.
(d) What is the nullity of A, that is, the dimension of null(A)? No justification necessary.
Transcribed Image Text:Consider the matrices -3 17 -1 9. [1 0 3 -6 4 12 1 -5 0 -3 A = 3 -1 11 4 24 and R = 0 0 1 3 0 0 0 0 4 8 1 15 10 1 18 You may assume that R is the reduced echelon form (RREF) of A. (a) Find a basis for the column space col(A). You must justify your answer. (b) Find a basis for the null space null(A). You must justify your answer. (c) What is the rank of A, that is, the dimension of col(A)? No justification necessary. (d) What is the nullity of A, that is, the dimension of null(A)? No justification necessary.
For part (a), a basis for col(A) is
2
2
4
which are the first, second, and fourth columns of A. For part (b), a basis for null(A) is
-3
For parts (c) and (d), the rank of A is 3 (since a basis for col(A) has three vectors in it) and the nullity of A
is 2 (since a basis for null(A) has two vectors in it).
Transcribed Image Text:For part (a), a basis for col(A) is 2 2 4 which are the first, second, and fourth columns of A. For part (b), a basis for null(A) is -3 For parts (c) and (d), the rank of A is 3 (since a basis for col(A) has three vectors in it) and the nullity of A is 2 (since a basis for null(A) has two vectors in it).
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