Consider the Lewis structure for H2C3H2, how many o and n bonds does it contain? O 8 0, 2 n O 7 0,1 n O 8 0,0 n O 6 0, 2 n

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### Understanding Lewis Structures in Organic Chemistry

#### Question:
Consider the Lewis structure for \( H_2C_3H_2 \). How many \( \sigma\) and \( \pi \) bonds does it contain?

#### Answer Options:
- \( 8 \sigma, 2 \pi \)
- \( 7 \sigma, 1 \pi \)
- \( 8 \sigma, 0 \pi \)
- \( 6 \sigma, 2 \pi \)

#### Detailed Explanation:

To determine the number of \( \sigma \) and \( \pi \) bonds in the molecule \( H_2C_3H_2 \), let's first analyze its structure.

1. **Lewis Structure Analysis**:
    - Each carbon (C) can form 4 bonds, and each hydrogen (H) can form 1 bond.
    - Arrange the three carbon atoms in a chain. The hydrogens will attach to the carbons, paying attention to valence requirements.

2. **Identifying Sigma (\( \sigma \)) Bonds**:
    - Sigma bonds are the single bonds that form by the head-on overlapping of orbitals.
    - Every single covalent bond consists of one \( \sigma \) bond.
    - Double and triple bonds contain one \( \sigma \) bond each.

3. **Identifying Pi (\( \pi \)) Bonds**:
    - Pi bonds occur in double or triple bonds, alongside sigma bonds.
    - Double bonds contain one \( \pi \) bond.
    - Triple bonds contain two \( \pi \) bonds.

By carefully drawing the molecule's structure, one can count the number of \( \sigma \) and \( \pi \) bonds to determine the correct answer from the provided options. 

This is a multiple-choice question often used to test knowledge in organic chemistry, specifically in the context of bonding and molecular structure.

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This transcription method not only states the question and answers but also provides a step-by-step explanation that can help students learn the underlying concepts in an educational context.
Transcribed Image Text:### Understanding Lewis Structures in Organic Chemistry #### Question: Consider the Lewis structure for \( H_2C_3H_2 \). How many \( \sigma\) and \( \pi \) bonds does it contain? #### Answer Options: - \( 8 \sigma, 2 \pi \) - \( 7 \sigma, 1 \pi \) - \( 8 \sigma, 0 \pi \) - \( 6 \sigma, 2 \pi \) #### Detailed Explanation: To determine the number of \( \sigma \) and \( \pi \) bonds in the molecule \( H_2C_3H_2 \), let's first analyze its structure. 1. **Lewis Structure Analysis**: - Each carbon (C) can form 4 bonds, and each hydrogen (H) can form 1 bond. - Arrange the three carbon atoms in a chain. The hydrogens will attach to the carbons, paying attention to valence requirements. 2. **Identifying Sigma (\( \sigma \)) Bonds**: - Sigma bonds are the single bonds that form by the head-on overlapping of orbitals. - Every single covalent bond consists of one \( \sigma \) bond. - Double and triple bonds contain one \( \sigma \) bond each. 3. **Identifying Pi (\( \pi \)) Bonds**: - Pi bonds occur in double or triple bonds, alongside sigma bonds. - Double bonds contain one \( \pi \) bond. - Triple bonds contain two \( \pi \) bonds. By carefully drawing the molecule's structure, one can count the number of \( \sigma \) and \( \pi \) bonds to determine the correct answer from the provided options. This is a multiple-choice question often used to test knowledge in organic chemistry, specifically in the context of bonding and molecular structure. --- This transcription method not only states the question and answers but also provides a step-by-step explanation that can help students learn the underlying concepts in an educational context.
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