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Draw the Lewis Structure of NO21 (OR N O2 minus). How many resonance structures can you draw?

Draw the Lewis Structure of NO21 (OR N O2 minus). How many resonance structures can you draw?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** Draw the Lewis Structure of NO₂⁻¹ (OR N O₂ minus). How many resonance structures can you draw? **Answer:** - Box to input answer: [ ] --- **Explanation:** The question asks students to draw the Lewis structure of the nitrite ion (NO₂⁻) and determine the number of resonance structures. To answer this, students would: 1. Calculate total valence electrons: Nitrogen has 5 valence electrons, each oxygen has 6, and there is one additional electron due to the negative charge, giving a total of 18 valence electrons. 2. Draw a skeleton structure with nitrogen as the central atom and oxygen atoms bonded to it. 3. Distribute the remaining electrons to satisfy the octet rule, initially placing lone pairs on the oxygen atoms, and then on nitrogen if extra electrons remain. 4. Create double bonds as necessary to ensure all atoms satisfy the octet rule. 5. Identify resonance structures: The bond can shift between nitrogen and either oxygen, resulting in at least two equivalent resonance structures where the double bond and lone pairs swap positions.
Transcribed Image Text:**Question:** Draw the Lewis Structure of NO₂⁻¹ (OR N O₂ minus). How many resonance structures can you draw? **Answer:** - Box to input answer: [ ] --- **Explanation:** The question asks students to draw the Lewis structure of the nitrite ion (NO₂⁻) and determine the number of resonance structures. To answer this, students would: 1. Calculate total valence electrons: Nitrogen has 5 valence electrons, each oxygen has 6, and there is one additional electron due to the negative charge, giving a total of 18 valence electrons. 2. Draw a skeleton structure with nitrogen as the central atom and oxygen atoms bonded to it. 3. Distribute the remaining electrons to satisfy the octet rule, initially placing lone pairs on the oxygen atoms, and then on nitrogen if extra electrons remain. 4. Create double bonds as necessary to ensure all atoms satisfy the octet rule. 5. Identify resonance structures: The bond can shift between nitrogen and either oxygen, resulting in at least two equivalent resonance structures where the double bond and lone pairs swap positions.
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