Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core cross section area A, and core diameter are given. Note that the core length l is equal to π times the core diameter. Answer the questions and pick an answer from the given choices. (a) Find the value of the inductor 1) 1.55 H 2) 0.82 H 3) 3.82 H 4) 12.05 H

Q: A magnetic core with an air gap is shown below. For a relative permeability is 3500, and the space…

A:

Q: A ten-turn solenoid has a ferromagnetic core with a relative permeability of 10,000. The length of…

A: N=10 Permeability =10000 Length l =10cm Area A =1 cm2

Q: A magnetic core with an air gap is shown below. For a relative permeability is 3500, and the space…

A: Transformer question

Q: H+ 7 cm 30 cm +4 7 cm 7 cm -0.07 cm 30 cm- +7 cm+ 300 turns 30 cm- 0.05 cm cm Core depth = 5 cm

A: Given data Relative permeability; μr=1500 Core depth=5 cm Number of turns on the center lag of the…

Q: Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core…

A: Nearly how long will it take the inductor to fully charge (i.e., reach steady-state)? 1) 1.5 sec 2)…

Q: Amagnetic field is being generated by a current of 2.0A flowing through 180 turns of wire on a core…

A: flux = MMFreluctance MMF = No. of turns * current in the coil .  Given current in the coil = 2 amps…

Q: Nb3Sn and GaV are candidates for a superconducting application, when the magnetic field is 150,000…

A: Both Nb3Sn and GaV superconductors are used for the high field superconducting electromagnets. The…

Compensation Techniques

The compensation techniques are the methods that are employed in the electrical control systems to enhance the performance of the system. The performance are generally affected by the factors like lag in the compensating devices, slow response of the system of the components like sensors used in the control system. The basic compensation technique involves lag compensation, lead compensation or the combination of the both.