Consider the indefinite integral I = P05 D7ESIJOAIPO5 D7 where sz + 6 z2 + 6z +t f(z) = a) Enter the value of s for which I can be evaluated directly to a function of the form log (lg(z)|) + C. b) Now suppose s is some real number different from the answer to part a). Enter the value for t for which I can be best solved by writing B f(z) = z+ 6 c) Again suppose s is some real number different from the answer to part a). Enter the values of t and r such that I can be best solved by writing В f(z) = (z +r) (z+r)- t = D7E 07ESIJO d) Now suppose s =1 and t = -16. i) (1 point.) Choose the most suitable of the following expressions that will allow you to evaluate the integral. f(z) = ... D7E z+8 PO5 D7ESIJOAIPO5 D7 z+8 0 4 + + D7E3IJO O Az+B Cz+D D7ESIJOAIPO5 z-2 z+8 Cz+D + z-8 z+2 Ar+B Cz+D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the indefinite integral
D7ESIJQA1PO5
ESIJOAIP05
D7ESIJOA
I:
f(z) dz
D7ESIJOAT
D7E
where
D7E
D7E
sz + 6
72 + 6z +t
f(1) =
a) Enter the value of s for which I can be evaluated directly to a function of the form log (lg(z)|) + C.
P05
D7E3
A1P05
D7E3IJO
07E
s =
D7ESIJOAIPO5
D7E
b) Now suppose s is some real number different from the answer to part a). Enter the value for t for which I can be best solved by writing
A
f(z) =
B
I+6
D7E
t =
c) Again suppose s is some real number different from the answer to part a). Enter the values of t and r such that I can be best solved by writing
B
f(z) =
D7E
(z + r)
(z +r)2
t =
PO5
D7ESI
P05
D7ES
D7E
d) Now suppose s = 1 and t = -16.
D7ESIJOA
D7E3
i) (1 point.) Choose the most suitable of the following expressions that will allow you to evaluate the integral. f(r) = ...
D7E
D7E3IJOA1P05
D7E3IJOAIPO5
D7ESIJOA1POS
D7E
PO5 D7ESIJQA1P05 D7E3IJ
P05
D7E3
D7E
O 4+2 +C
05
D7
iz +16
O Az+B + Cx+D
I-2
z+8
D7ESIJO
D7E
O Az+B
I+2
Cr+D
7-8
O Az+B
Cr+D
Transcribed Image Text:Consider the indefinite integral D7ESIJQA1PO5 ESIJOAIP05 D7ESIJOA I: f(z) dz D7ESIJOAT D7E where D7E D7E sz + 6 72 + 6z +t f(1) = a) Enter the value of s for which I can be evaluated directly to a function of the form log (lg(z)|) + C. P05 D7E3 A1P05 D7E3IJO 07E s = D7ESIJOAIPO5 D7E b) Now suppose s is some real number different from the answer to part a). Enter the value for t for which I can be best solved by writing A f(z) = B I+6 D7E t = c) Again suppose s is some real number different from the answer to part a). Enter the values of t and r such that I can be best solved by writing B f(z) = D7E (z + r) (z +r)2 t = PO5 D7ESI P05 D7ES D7E d) Now suppose s = 1 and t = -16. D7ESIJOA D7E3 i) (1 point.) Choose the most suitable of the following expressions that will allow you to evaluate the integral. f(r) = ... D7E D7E3IJOA1P05 D7E3IJOAIPO5 D7ESIJOA1POS D7E PO5 D7ESIJQA1P05 D7E3IJ P05 D7E3 D7E O 4+2 +C 05 D7 iz +16 O Az+B + Cx+D I-2 z+8 D7ESIJO D7E O Az+B I+2 Cr+D 7-8 O Az+B Cr+D
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