Consider the hypothesis statement to the right using a = 0.10 and the data to the right from two independent samples.a) Calculate the appropriate test statistic and interpret the result.b) Calculate the p-value and interpret the result.Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal tableX = 80X2 = 72o1 = 30n1 = 5502 = 17n2 = 50a) The test statistic is 1.70(Round to two decimal places as needed)Determine the appropriate critical value(s).The critical value(s) is(are)(Round to two decimal places as needed Use a comma to separate answers as needed.)

We have given that Sample mean (x̅1) = 80Sample mean (x̅2) = 72Sample size (n1) = 50Sample size (n2)…

Answered: Consider the hypothesis statement to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 7g. What are the critical value(s)?The critical value(s) is/are enter your response here. (Round to three decimal places as needed. Use a comma to separate answers as needed.)Part 8h. What is the area of the critical region?The area is enter your response here. (Round to two decimal places as needed.)
Complete parts (a) and (b) below. Click here to view Page 1 of the table of areas under the standard normal curve. Click here to view Page 2 of the table of areas under the standard normal curve. a. The test statistic in a right-tailed test is z= 1.71. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is (Round to three decimal places as needed.) This P-value V sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is V the significance level. b. The test statistic in a right-tailed test is z= - 0.82. Determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is (Round to three decimal places as needed.) This P-value sufficient evidence to reject the null hypothesis in…
A transportation agency would like to compare the average amount of time it takes passengers to pass through airport security at two locations during peak times. The following table summarizes in minutes the results of two random samples from each airport. Use the table to complete parts a through c. Sample mean Sample standard deviation Sample size Location 1 Location 2 14.5 11.6 5.9 4.6 22 Determine the null and alternative hypotheses for the test. Hoi Hi-H2 S 0 H₁ H₁ H₂ > 0 Calculate the appropriate test statistic and interpret the result. The test statistic is (Round to two decimal places as needed.) Because the test statistic 29 The critical value(s) is (are). (Round to two decimal places as needed. Use a comma to separate answers as needed.) b. Identify the p-value from part a and interpret the result. The p-value is (Round to three decimal places as needed.) Interpret the result. Choose the correct answer below. the null hypothesis. O A. Since the p-value is less than the…
Listed below are the numbers of years that archbishops and monarchs in a certain country lived after their election or coronation. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.10 significance level to test the claim that the mean longevity for archbishops is less than the mean for monarchs after coronation, All measurements are in years. ok nch Click the icon to view the table of longevities of archbishops and monarchs. What are the null and alternative hypotheses? Assume that population 1 consists of the longevity of archbishops and population 2 consists of the longevity of monarchs. O B. Ho H1 = H2 H, 2 OA. Ho H1 SH2 correct: er Conter YC. Ho H1 = H2 H, H H2 O D. Ho H1 2 H H P2 for Succes media Lib The test statistic is. (Round to two decimal places as needed.) hase Optio rse Tools
Data on the weights (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? OA. Ho: H₁ H₂ H₁: Hy #4₂ OC, Hoi ky tuy H₁: Hy O L P H command n X S Time Remaining: 01:13:11 V : • Diet H₁ 30 0.79861 lb 0.00445 lb ; x { [ option ? I Regular H₂ 30 0.80936 lb 0.00742 lb Next delete
A 0.1 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is less than 0.5. Assume that sample data consists of 78 girls in 169 births, so the sample statistic of 613 results in a z score that is 1 standard deviation below 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p≠0.5H1: p<0.5B.H0: p=0.5H1: p≠0.5C.H0: p=0.5H1: p<0.5D.H0: p=0.5H1: p>0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? Normal distribution Student (t) distribution χ2Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Right-tailed…
A 0.01 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is different from 0.5. Assume that sample data consists of 55 girls in 100 births, so the sample statistic of 1120 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.A.H0: p=0.5H1: p≠0.5B.H0: p=0.5H1: p>0.5C.H0: p=0.5H1: p<0.5D.H0: p≠0.5H1: p=0.5Part 2b. What is the value of α?α=enter your response here (Type an integer or a decimal.)Part 3c. What is the sampling distribution of the sample statistic? χ2 Normal distribution Student (t) distribution
Use the Excel printout to answer the following questions. t-Test: Two-Sample Assuming Equal Variances E Variable 1 Variable 2 Mean 28.671 28.215 Variance 5.061 2.225 Observations 8 7 Pooled Variance 3.752 Hypothesized Mean Difference df 13 t Stat 0.455 P(T <= t) one-tail 0.328 t Critical one-tail 1.771 P(T <= t) two-tail 0.657 t Critical two-tail 2.160 In testing for a difference between the two population means, would you conclude that the assumption of a common variance is reasonable? O Yes, the ratio of the the larger variance to the smaller variance is less than three. O Yes, the ratio of the larger variance to the smaller variance is more than three. O No, the ratio of the larger variance to the smaller variance is less than three. O No, the ratio of the larger variance to the smaller variance is more than three. O It is not possible to check that assumption with the given information. What is the observed value of the test statistic? t = What are the degrees of freedom for the…
Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.05 significance level for both parts. Diet Regular H2 nts 34 0.80711 lb 34 0.79119 lb 0.00432 lb 0.00747 lb 車 ent a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? bra O B. Ho H1 H2 Hq: Hy < H2 O A. Ho: H1 = H2 on! O D. Hg: H1 = H2 O C. Ho H H2 The test statistic, t, is (Round to two decimal places as needed.) The P-value is |. (Round to three decimal places as needed.) State the conclusion for the test. n oonr of diet soda have mean weights that are lower than the mean weight
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
A 0.05 significance level is used for a hypothesis test of the claim that when parents use a particular method of gender selection, the proportion of baby girls is greater than 0.5. Assume that sample data consists of 78 girls in 144 births, so the sample statistic of 1324 results in a z score that is 1 standard deviation above 0. Complete parts (a) through (h) below.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1a. Identify the null hypothesis and the alternative hypothesis. Choose the correct answer below.Part 4d. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed Right-tailed Two-tailedPart 5e. What is the value of the test statistic?The test statistic is enter your response here. (Type an integer or a decimal.)Part 6f. What is the P-value?The P-value is enter your response here. (Round to four decimal places as needed.)
Please answer the questions in the photo. For Question 1, B has been selected BUT that could possibly not be the right answer. Please select the correct answer for Question 1 & 2.

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