Consider the half-reaction for the reduction of Cd2+to Cd(s). Ecd² Cd Cd²+ (aq) + 2 e -Cd(s) Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0450 M solution of CdBr₂. Ecd = = -0.403 V V

Consider the half-reaction for the reduction of Cd2+to Cd(s). Ecd² Cd Cd²+ (aq) + 2 e -Cd(s) Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0450 M solution of CdBr₂. Ecd = = -0.403 V V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Consider the half-reaction for the reduction of Cd2+to Cd(s).
Ecd² Cd
Cd²+ (aq) + 2e-
Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0450 M solution of CdBr₂.
Ecd=
→ Cd(s)
Ecd=
= -0.403 V
Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0760 M NaOH solution that is saturated with
Cd(OH)2. The Ksp for Cd(OH)₂ is 7.2 x 10-¹5.
Calculate the potential of the cadmium electrode at 25 °C when immersed in a 0.0120 M Cd(NH3)2+ and 0.110 M NH,
solution. The 4 for Cd(NH3)2 + is 3.63 x 106.
V
V

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