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Consider the graph showing the emf as a function of temperature for the electrochemical cell made of the solutions of CuSO4 and Pb(NO3)2. 180 160 140 120 100 E, MV 60 40 20 0 620 640 T.K y=-1,411x + 1059, R²=0,998 660 680 700 Calculate the AS for the system in J.K-¹.

Consider the graph showing the emf as a function of temperature for the electrochemical cell made of the solutions of CuSO4 and Pb(NO3)2. 180 160 140 120 100 E, MV 60 40 20 0 620 640 T.K y=-1,411x + 1059, R²=0,998 660 680 700 Calculate the AS for the system in J.K-¹.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Consider the graph showing the emf as a function of temperature for the electrochemical cell made of the solutions of CuSO4 and Pb(NO3)2. 180 160 140 120 100 E, mV 60 40 20 0 620 640 T.K y=-1,411x + 1059, R²=0,998 660 680 700 Calculate the AS for the system in J.K-1.
Transcribed Image Text:Consider the graph showing the emf as a function of temperature for the electrochemical cell made of the solutions of CuSO4 and Pb(NO3)2. 180 160 140 120 100 E, mV 60 40 20 0 620 640 T.K y=-1,411x + 1059, R²=0,998 660 680 700 Calculate the AS for the system in J.K-1.
Expert Solution
Step 1

Given that, a plot of emf as a function of temperature for the electrochemical cell made of the solutions of CuSO4 and Pb(NO3)2.

Also, the equation from the graph is y = -1411x + 1059.

We have to calculate the entropy change of the system, ∆S.

Formula: The formula required to solve this problem is given below 

∆S = nFdEdT

Where n is the total number of electrons involved in the cell reaction,

F is Faraday's contact = 96500 C,

And dEdT is the temperature coefficient.

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