Consider the graph of f. f(z)dz (2) The shaded region over [0, 7] has an area of 314 and evaluate the following definite integrals. f(x) f(z)dx= [ fu - [ (2)=[ [f(z) + 6]dz (2) 1.12 7 8 9 10 f(z+6)dz a f(z)dz - 303. Use this information

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