Solve (x² 1 + 2y) dx + (1 - x²) dy = 0; when x = 2, y = 1 1) (x + 1 + 2 ln x 1) b. (x + 1) y = (x − 1) (x − 1 + 2 ln|x − 1|) c. (x 1) y = (x + 1) (x +1+2ln|x − 1|) a. (x + 1) y = (x Your answer is correct. The correct answer is: -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve (x²
1 + 2y) dx + (1 − x²) dy = 0; when x = 2, y = 1
−
a. (x+1)y=(x − 1)(x+1+2 ln|x - 1) ✓
b. (x + 1) y = (x
1) (x
- 1)
c. (x 1) y = (x + 1) (x + 1 + 2 ln x
1|)
Your answer is correct.
The correct answer is:
-
1 + 2 ln x
Transcribed Image Text:Solve (x² 1 + 2y) dx + (1 − x²) dy = 0; when x = 2, y = 1 − a. (x+1)y=(x − 1)(x+1+2 ln|x - 1) ✓ b. (x + 1) y = (x 1) (x - 1) c. (x 1) y = (x + 1) (x + 1 + 2 ln x 1|) Your answer is correct. The correct answer is: - 1 + 2 ln x
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