Consider the function g : (6, 0) → R given by, 3x g(x) : x-6 Then we have that lim g(x) =3 . %3D x→∞ Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then Ig(x) – 3| < e. The smallest value for M in terms of e is М — Note: • Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077. • the Maple syntax for |æ| is abs (x), and the syntax for e is epsilon.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the function g : (6, 00) → R given by,
3x
g(x) =
x-6
Then we have that
lim g(x) = 3.
Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then
|g(x) – 3| < e.
The smallest value for M in terms of e is
M =
Note:
Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077.
the Maple syntax for x is abs (x), and the syntax for e is epsilon.
Transcribed Image Text:Consider the function g : (6, 00) → R given by, 3x g(x) = x-6 Then we have that lim g(x) = 3. Suppose that e > 0. Find the smallest value for M > 6 such that if x > M then |g(x) – 3| < e. The smallest value for M in terms of e is M = Note: Enter your answer as a fraction, for example 25/13, not as a decimal, eg not as 1.923077. the Maple syntax for x is abs (x), and the syntax for e is epsilon.
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