Consider the function f(z) whose second derivative is f" (z) = 2z+5 sin(z). If f(0) = 4 and f'(0) = 6, find the actual function f(z). Student solution. First we begin by recalling the following antiderivatives: antiderivative of z = antiderivative of z = antiderivative of cos(z) =| antiderivative of sin(z) =. Using these rules, we can write for f'(z) the following f'(z) =+C for some constant c The value for the constant c is given as Thus the first derivative f'(z) equals f (2) =D Next we can compute f up to a constant co, namely: f(2) =+G. The value for the constant co is given as Thus the function f(z) equals f(r) =.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the function f(z) whose second derivative is
f" (1) = 21 +5 sin(z).
If f(0) = 4 and f'(0) = 6, find the actual function f(x).
Student solution. First we begin by recalling the following antiderivatives:
antiderivative of z =
antiderivațive of z =
antiderivative of cos(z) =|
antiderivative of sin(z) = .
Using these rules, we can write for f'(z) the following
f'(=) =to
for some constant c.
The value for the constant c is given as
Thus the first derivative f'(z) equals
f(2) =.
Next we can compute f up to a constant co, namely:
f(x) =+co
The value for the constant co is given as
Thus the function f(x) equals
f(x)
Transcribed Image Text:Consider the function f(z) whose second derivative is f" (1) = 21 +5 sin(z). If f(0) = 4 and f'(0) = 6, find the actual function f(x). Student solution. First we begin by recalling the following antiderivatives: antiderivative of z = antiderivațive of z = antiderivative of cos(z) =| antiderivative of sin(z) = . Using these rules, we can write for f'(z) the following f'(=) =to for some constant c. The value for the constant c is given as Thus the first derivative f'(z) equals f(2) =. Next we can compute f up to a constant co, namely: f(x) =+co The value for the constant co is given as Thus the function f(x) equals f(x)
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