Consider the formation of gibbsite from dissolved aluminum as depicted below:Al3+ + OH- --> Al(OH)3 (gibbsite)a) balance this reaction (if necessary)b) predict how many mg of Al(OH)3 would be formed if 3 mg of Al3+ are dissolved in 1 l of water and “unlimited” OH- is available (assume this reaction goes completely to the right; there’s no worry about equilibrium dissolved Al3+). ### Formation of Gibbsite from Dissolved AluminumConsider the formation of gibbsite from dissolved aluminum as depicted below:\[ \text{Al}^{3+} + \text{OH}^- \rightarrow \text{Al(OH)}_3 \text{ (gibbsite)} \]**a)** Balance this reaction (if necessary) and **b)** Predict how many mg of Al(OH)₃ would be formed if 3 mg of Al³⁺ are dissolved in 1 L of water and "unlimited" OH⁻ is available (assume this reaction goes completely to the right; there’s no worry about equilibrium dissolved Al³⁺).

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Answered: Consider the formation of gibbsite from…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the formation of gibbsite from dissolved aluminum as depicted below:

Al³⁺ + OH^- --> Al(OH)_{3 (gibbsite)}

a) balance this reaction (if necessary)
b) predict how many mg of Al(OH)₃ would be formed if 3 mg of Al³⁺ are dissolved in 1 l of water and “unlimited” OH^- is available (assume this reaction goes completely to the right; there’s no worry about equilibrium dissolved Al³⁺).

### Formation of Gibbsite from Dissolved Aluminum

Consider the formation of gibbsite from dissolved aluminum as depicted below:

\[ \text{Al}^{3+} + \text{OH}^- \rightarrow \text{Al(OH)}_3 \text{ (gibbsite)} \]

**a)** Balance this reaction (if necessary) and
**b)** Predict how many mg of Al(OH)₃ would be formed if 3 mg of Al³⁺ are dissolved in 1 L of water and "unlimited" OH⁻ is available (assume this reaction goes completely to the right; there’s no worry about equilibrium dissolved Al³⁺).

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