In theory, sodium (Na) metal could be used in place of magnesium (Mg) in the preparation of titanium metal from TiO2. From Lecture 3-1, slide 4: TiO2 + 2 Mg --> 2 MgO + Ti Which of the following statements would be true if sodium was used instead of magnesium? Group of answer choices None of the other three statements are true. The reaction would not proceed with sodium because sodium oxide (analogous to the MgO product that forms) can't exist You would need 4 moles of Na because the sodium oxide product has a formula of Na2O. The reaction could not be done because sodium metal does not actually exist
In theory, sodium (Na) metal could be used in place of magnesium (Mg) in the preparation of titanium metal from TiO2. From Lecture 3-1, slide 4: TiO2 + 2 Mg --> 2 MgO + Ti Which of the following statements would be true if sodium was used instead of magnesium? Group of answer choices None of the other three statements are true. The reaction would not proceed with sodium because sodium oxide (analogous to the MgO product that forms) can't exist You would need 4 moles of Na because the sodium oxide product has a formula of Na2O. The reaction could not be done because sodium metal does not actually exist
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter18: Representative Metals, Metalloids, And Nonmetals
Section: Chapter Questions
Problem 52E: The reaction of calcium hydride, CaH2, with water can be characterized as a Lewis acid-base...
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In theory, sodium (Na) metal could be used in place of magnesium (Mg) in the preparation of titanium metal from TiO2.
From Lecture 3-1, slide 4: TiO2 + 2 Mg --> 2 MgO + Ti
Which of the following statements would be true if sodium was used instead of magnesium?
Group of answer choices
None of the other three statements are true.
The reaction would not proceed with sodium because sodium oxide (analogous to the MgO product that forms) can't exist
You would need 4 moles of Na because the sodium oxide product has a formula of Na2O.
The reaction could not be done because sodium metal does not actually exist
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