**Consider the following velocity versus time graph for a moving car.**(An image of a velocity versus time graph is shown. The x-axis is labeled "Time (s)" and the y-axis is labeled "Velocity (m/s)". The graph is plotted as follows: - At \( t = 0 \) to \( t = 20 \) seconds, the velocity decreases linearly from 20 m/s to -20 m/s.- From \( t = 20 \) to \( t = 50 \) seconds, the velocity remains constant at -20 m/s.- From \( t = 50 \) to \( t = 80 \) seconds, the velocity increases linearly back to 20 m/s.)**What would the car's position be at 80.0 s if it started at a position \( x_0 = -10.0 \, \text{m} \) at \( t = 0 \text{ s}? **

The acceleration can be found by finding the slope of the graph For 0 to 30 s: a = (-20 - 20)30 =…

Consider the following velocity versus time graph for a moving car. Velocity (m/s) 20 10 -10 -20 -30 Time (s) 10 20 30 40 50 60 70 80 What would the car's position be at 80.0 s if it started at a position x, = -10.0 m at t = 0 s?

Consider the following velocity versus time graph for a moving car. Velocity (m/s) 20 10 -10 -20 -30 Time (s) 10 20 30 40 50 60 70 80 What would the car's position be at 80.0 s if it started at a position x, = -10.0 m at t = 0 s?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

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**Consider the following velocity versus time graph for a moving car.**

(An image of a velocity versus time graph is shown. The x-axis is labeled "Time (s)" and the y-axis is labeled "Velocity (m/s)". The graph is plotted as follows:
- At \( t = 0 \) to \( t = 20 \) seconds, the velocity decreases linearly from 20 m/s to -20 m/s.
- From \( t = 20 \) to \( t = 50 \) seconds, the velocity remains constant at -20 m/s.
- From \( t = 50 \) to \( t = 80 \) seconds, the velocity increases linearly back to 20 m/s.)

**What would the car's position be at 80.0 s if it started at a position \( x_0 = -10.0 \, \text{m} \) at \( t = 0 \text{ s}? **

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