Consider the following variation on MergeSort: instead of dividing a list (say, of integers) evenly (that is, half and half or half and half plus 1) at all levels of recursion, we choose to divide a list this way - a left list that consists of exactly one integer and a right list that consists of the remaining integers. The time-complexity of this variation of MergeSort is: (a) O(n log n) (b) O(n²) (c) O(n) (d) none of the above
Consider the following variation on MergeSort: instead of dividing a list (say, of integers) evenly (that is, half and half or half and half plus 1) at all levels of recursion, we choose to divide a list this way - a left list that consists of exactly one integer and a right list that consists of the remaining integers. The time-complexity of this variation of MergeSort is: (a) O(n log n) (b) O(n²) (c) O(n) (d) none of the above
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![Consider the following variation on MergeSort: instead of dividing a list (say, of integers) evenly (that
is, half and half or half and half plus 1) at all levels of recursion, we choose to divide a list this way
- a left list that consists of exactly one integer and a right list that consists of the remaining integers.
The time-complexity of this variation of MergeSort is:
(a) O(n log n)
(b) O(n²)
(c) O(n)
(d) none of the above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F40a93fbf-cd84-46cf-939a-402485a39dd9%2Ffa105c55-37f5-4032-b38e-be9f7225aba2%2Fu257redg_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the following variation on MergeSort: instead of dividing a list (say, of integers) evenly (that
is, half and half or half and half plus 1) at all levels of recursion, we choose to divide a list this way
- a left list that consists of exactly one integer and a right list that consists of the remaining integers.
The time-complexity of this variation of MergeSort is:
(a) O(n log n)
(b) O(n²)
(c) O(n)
(d) none of the above
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