Question: If the three operations were combined, O(logN) + O(N) * O(logN) +1, the overall algorithm cost would be: A. O(N) B. O(logN) C. O(logN) + O(N) D. O(NlogN) What is the dominate term of each function? 3n²+4n-3 7n + 4n² -7n + 5 5nlog(n) + 2n – 4
Question: If the three operations were combined, O(logN) + O(N) * O(logN) +1, the overall algorithm cost would be: A. O(N) B. O(logN) C. O(logN) + O(N) D. O(NlogN) What is the dominate term of each function? 3n²+4n-3 7n + 4n² -7n + 5 5nlog(n) + 2n – 4
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![Question: If the three operations were combined, O(logN) + O(N) * O(logN) +1, the overall algorithm cost
would be:
A. O(N)
B. O(logN)
C. O(logN) + O(N)
D. O(NlogN)
What is the dominate term of each function?
3n?+4n-3
7n + 4n? -7n + 5
5nlog(n) + 2n– 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F64d9ce60-b001-4270-8dd6-e9babf85f2bf%2F3393547b-370d-4323-8a3f-7d1ff0c9c33e%2F9ykkwap_processed.png&w=3840&q=75)
Transcribed Image Text:Question: If the three operations were combined, O(logN) + O(N) * O(logN) +1, the overall algorithm cost
would be:
A. O(N)
B. O(logN)
C. O(logN) + O(N)
D. O(NlogN)
What is the dominate term of each function?
3n?+4n-3
7n + 4n? -7n + 5
5nlog(n) + 2n– 4
![What does Recursion Require?
1. Termination Condition
2. Call the Clone (same function)
3. Move towards Termination Condition
Label the Recursion Requirements.
Show the Activation Stack for n = 4.
int fact (int n)
{
int result;
if (n==1)
return 1;
result = fact (n-1) * n:
return result;
boolean isPal (String s)
Show the Activation Stack for "ZEROREZ"
if (s.length () -- 0 | 8.length ()
// if length =0 OR 1 then it is
return true;
if (charAt (0)
// check first and last char of String:
// if same then do same for substring
// for substring and carry on this
// remove first and last char.
return isPal (s.substring (1, 3.length ()-1));
1)
S.charAt (s.length ()-1))
// if its not the case than string is not.
return false;
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F64d9ce60-b001-4270-8dd6-e9babf85f2bf%2F3393547b-370d-4323-8a3f-7d1ff0c9c33e%2Ff84z89c_processed.png&w=3840&q=75)
Transcribed Image Text:What does Recursion Require?
1. Termination Condition
2. Call the Clone (same function)
3. Move towards Termination Condition
Label the Recursion Requirements.
Show the Activation Stack for n = 4.
int fact (int n)
{
int result;
if (n==1)
return 1;
result = fact (n-1) * n:
return result;
boolean isPal (String s)
Show the Activation Stack for "ZEROREZ"
if (s.length () -- 0 | 8.length ()
// if length =0 OR 1 then it is
return true;
if (charAt (0)
// check first and last char of String:
// if same then do same for substring
// for substring and carry on this
// remove first and last char.
return isPal (s.substring (1, 3.length ()-1));
1)
S.charAt (s.length ()-1))
// if its not the case than string is not.
return false;
}
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