Consider the following system of linear equations. 2x -3z=-12 -3x-2y +z = 7 3y + 4z = 9 Solve the system by completing the steps below to produce a reduced row-echelon form. R₁, R₂, and R3 denote the first, second, and third rows, respectively. The arrow notation (→) stands for "replaces," where the expression on the left of the arrow replaces the expression on the right. Here is the augmented matrix: Enter the missing coefficients for the row operations. (1) (2) O-R₁-R₁: -R-RR. 2 0-3 -12 -3 -2 1 7 0 3 08 R 1 10 -3 -2 1 03 0-2 0 3 0 01 10- in 1 49 دا را C4 3/2 72 I 4 -t -6 -6 r -6 6 -11 16 8 08 X 5

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