Consider the following system at equilibrium where AHº =-10.4 kJ, and K. = 55.6, at 698 K. %3D H2(g) + I»(g)2HI(g) When 0.21 moles of I-(g) are added to the equilibrium system at constant temperature: The value of K The value of Qe The reaction must Orun in the forward direction to restablish equilibrium. Orun in the reverse direction to restablish equilibrium. Oremain the same. It is already at equilibrium. The concentration of H2 will

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Chapter1: Chemical Foundations
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the pull downs are either, increase, decrease, or remain the same
**Chemical Equilibrium Analysis**

Consider the following chemical system at equilibrium where the change in enthalpy, ΔH° = -10.4 kJ, and the equilibrium constant, Kc = 55.6, at a temperature of 698 K:

\( \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \)

When 0.21 moles of \( \text{I}_2(g) \) are added to the equilibrium system at a constant temperature, evaluate the following:

1. The value of \( K_c \). 
2. The value of \( Q_c \) compared to \( K_c \).
3. Determine if the reaction must:
   - Run in the forward direction to reestablish equilibrium.
   - Run in the reverse direction to reestablish equilibrium.
   - Remain the same as it is already at equilibrium.

4. Calculate the change in the concentration of \( \text{H}_2 \).

Once the reaction adjustments are made, use the provided interface to enter your answers and submit them for evaluation. To adjust your responses or make corrections, click "Retry Entire Group." You have 9 more group attempts remaining.
Transcribed Image Text:**Chemical Equilibrium Analysis** Consider the following chemical system at equilibrium where the change in enthalpy, ΔH° = -10.4 kJ, and the equilibrium constant, Kc = 55.6, at a temperature of 698 K: \( \text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g) \) When 0.21 moles of \( \text{I}_2(g) \) are added to the equilibrium system at a constant temperature, evaluate the following: 1. The value of \( K_c \). 2. The value of \( Q_c \) compared to \( K_c \). 3. Determine if the reaction must: - Run in the forward direction to reestablish equilibrium. - Run in the reverse direction to reestablish equilibrium. - Remain the same as it is already at equilibrium. 4. Calculate the change in the concentration of \( \text{H}_2 \). Once the reaction adjustments are made, use the provided interface to enter your answers and submit them for evaluation. To adjust your responses or make corrections, click "Retry Entire Group." You have 9 more group attempts remaining.
Expert Solution
Step 1

The reaction state at which the concentration of products and reactants become equal to each other is known as equilibrium. At equilibrium no formation of product or reactant takes place. However, the equilibrium of the reaction shift toward right and left depending upon the concentration change.

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